如何获得单个数组中具有最大差异的元素? [英] How to get the elements with maximum difference in the single array?

问题描述

假设a = [3,7，8,66,121,223,228]如何获得其中最大差异的元素? 我对此有解决方案，但是会比这更好的代码.

Suppose, a= [3,7, 8,66,121,223,228] how to get the elements with maximum difference among them? I have this solution to it but will appreciate better code than this.

let arr = []
a.sort((a,b)=>{
    return arr.push(a-b)
})
let index = arr.indexOf(Math.max(...arr))
a.sort((a,b)=> a-b).slice(index,index+2) 

我希望输出为[121,223]

I expect the output to be [121,223]

推荐答案

您可以检查每对具有最后发现对的对，并获得具有最大增量的对.

You could check each pair with the last found pair and get the one with the greatest delta.

var array = [3, 7, 8, 66, 121, 223, 228],
    result = array.reduce((r, b, i, { [i - 1]: a }) => {
        if (i === 0) return;
        if (i === 1 || b - a > r[1] - r[0]) return [a, b];
        return r;
    }, undefined);

console.log(result);

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