按值对动物园对象排序 [英] Sorting a zoo object by value

问题描述

我有一个动物园时间序列对象.如何在保留日期的同时按值对它进行排序?

I have a zoo time series object. How do I sort it by value, while preserving the dates?

如果这是我的系列作品

2013-10-02 2013-10-03 2013-10-04 2013-10-07 2013-10-08 2013-10-09 
-0.02      0.00       0.00       0.04       0.00       0.02

结果应为:

2013-10-02 2013-10-03 2013-10-04 2013-10-08 2013-10-09 2013-10-07
-0.02      0          0          0          0.02       0.04

普通sort按日期(非值)对Zoo对象进行排序.动物园对象(日期，1个值系列)的值是NULL，因此无法指定我要按第二列排序.

Ordinary sort sorts the zoo object by date (not value). zoo object (date, 1 value series) has dim NULL, so it's not possible to specify that I want to sort by the second column.

推荐答案

在数据框中使用数据并将其转换为"zoo"对象:

Using your data in a data frame and converting to a "zoo" object:

df <- data.frame(Dates = as.Date(c("2013-10-02", "2013-10-03", "2013-10-04",
                                   "2013-10-07", "2013-10-08", "2013-10-09")),
                 Values = c(-0.02, 0.00, 0.00, 0.04, 0.00, 0.02))
library("zoo")
zdf <- zoo(df$Values, df$Dates)

虽然@Joshua是正确的，但是您始终可以转换回数据框表示形式并进行排序，而您只需要处理整个过程中的日期保留即可.例如:

Whilst @Joshua is correct, you can always convert back to a data frame representation and sort that, you just have to handle the preservation of the dates through the process. For example:

df2 <- as.data.frame(zdf)
df2 <- transform(df2, Dates = as.Date(rownames(df2)))

现在排序df2

df2[order(df2$zdf), ]

R> df2[order(df2$zdf), ]
             zdf      Dates
2013-10-02 -0.02 2013-10-02
2013-10-03  0.00 2013-10-03
2013-10-04  0.00 2013-10-04
2013-10-08  0.00 2013-10-08
2013-10-09  0.02 2013-10-09
2013-10-07  0.04 2013-10-07

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