按降序对数组值进行排序 [英] Sorting array value in descending order

问题描述

如何按降序对值进行排序?我已经尝试过arsort();但这对我来说不起作用:

How can I sort the values in descending order? I've tried arsort(); but it doesn't work in my case:

$text1 = 'Android SDK, application, familiar with MVP architecture, android studio, angular, angular js';

$skill = array("android sdk"=>"3", "application"=>"1", "angular"=>"2", "android studio"=>"3", "angular js"=>"3");

foreach ($skill as $skills => $weight)            {

if (preg_match_all("~\b$skills\b~i", $text1, $matchWords)) {  

$matchWords = $matchWords[0];

$matchWords = array_unique($matchWords);

}  

$text2 = 'Native Android development';

// Filter $words, keep only the items that are not present in $text2
$missing = array_filter(
    $matchWords,
    function($w) use ($text2) {
        // return TRUE when $w is not in $text
        return preg_match('/\b'.preg_quote($w, '/').'\b/i', $text2) == 0;
});


$weight = array($weight);
$dev = array_combine($missing, $weight);
arsort($dev);

foreach($dev as $x => $x_value) 
     echo "Key: " . $x . " Value: " . $x_value;
     echo "<br>";

}

输出:

键:Android SDK值:3 密钥:应用程序值:1 关键点:角度值:2 关键:android studio价值:3 密钥:angular js值:3

Key: Android SDK Value: 3 Key: application Value: 1 Key: angular Value: 2 Key: android studio Value: 3 Key: angular js Value: 3

但是我想得到这个结果:

But I'd like to get this result:

键:Android SDK值:3 关键:android studio价值:3 密钥:angular js值:3 关键点:角度值:2 密钥:应用程序值:1

Key: Android SDK Value: 3 Key: android studio Value: 3 Key: angular js Value: 3 Key: angular Value: 2 Key: application Value: 1

我没有在建议的此处找到答案. >

I haven't found an answer here as suggested.

推荐答案

未正确排序数组的原因是因为您正在尝试对单个元素数组进行排序.如果在代码中放入调试打印，则在调用arsort时将看到$dev仅包含一个元素.您需要在循环中组装$dev，然后对其进行排序.尝试这样的事情:

The reason your array is not being sorted correctly is because you are attempting to sort a single element array. If you put debugging prints in your code you will see that $dev only ever has one element when you call arsort. You need to assemble $dev in the loop, then sort it afterwards. Try something like this:

$text1 = 'Android SDK, application, familiar with MVP architecture, android studio, angular, angular js';
$text2 = 'Native Android development';
$skill = array("android sdk"=>"3", "application"=>"1", "angular"=>"2", "android studio"=>"3", "angular js"=>"3");

foreach ($skill as $skills => $weight) {
    if (preg_match_all("~\b$skills\b~i", $text1, $matchWords)) {  
        $matchWords = $matchWords[0];
        $matchWords = array_unique($matchWords);
    }  
    // Filter $words, keep only the items that are not present in $text2
    $missing = array_filter(
        $matchWords,
        function($w) use ($text2) {
            // return TRUE when $w is not in $text
            return preg_match('/\b'.preg_quote($w, '/').'\b/i', $text2) == 0;
    });

    if (count($missing)) $dev[$missing[0]] = $weight;
}
arsort($dev);

foreach($dev as $x => $x_value) {
    echo "Key: " . $x . " Value: " . $x_value;
    echo "<br>";
}

输出:

Key: Android SDK Value: 3
Key: android studio Value: 3
Key: angular js Value: 3
Key: angular Value: 2
Key: application Value: 1

您的循环代码可以大大简化，但这是另一个问题...

Your loop code could be simplified greatly but that's another question...

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