尝试使命令静音时,Dos2unix无法正常工作 [英] Dos2unix not working when trying to silence command
问题描述
我是这样从Python内部调用dos2unix的:
I was calling dos2unix from within Python this way:
call("dos2unix " + file1, shell=True, stdout=PIPE)
无论如何,我都是这样做的:
However to silence the Unix output, I did this:
f_null = open(os.devnull, 'w')
call("dos2unix " + file1, shell=True, stdout=f_null , stderr=subprocess.STDOUT)
这似乎不起作用.该命令不再被调用,因为我在file1
与file2
上执行的差异(没有diff -y file1 file2 | cat -t
并且可以看到行尾未更改).
This doesn't seem to work. The command isn't being called anymore as the diff that I perform on the file1
against file2
(did a diff -y file1 file2 | cat -t
and could see the line endings hadn't changed).
file2
是我正在比较file1
的文件.它具有在包装盒上生成的Unix行尾.但是,file1
可能没有.
file2
is the file I am comparing file1
against. It has Unix line endings as it is generated on the box. However, there is a chance that file1
doesn't.
推荐答案
不确定,为什么,但是我会尝试消除您命令&周围的噪音"检查返回码:
Not sure, why but I would try to get rid of the "noise" around your command & check return code:
check_call(["dos2unix",file1], stdout=f_null , stderr=subprocess.STDOUT)
- 作为args列表而不是命令行传递(支持其中包含空格的文件!)
- 删除
shell=True
,因为dos2unix
不是内置的shell命令 - 使用
check_call
,因此引发异常,而不是无声地失败 - pass as list of args, not command line (support for files with spaces in it!)
- remove
shell=True
asdos2unix
isn't a built-in shell command - use
check_call
so it raises an exception instead of failing silently
无论如何,dos2unix
可能检测到输出不再是tty,并决定转储输出(dos2unix
可以从标准输入&至标准输出工作).我会解释一下.您可以通过重定向到 real 文件而不是os.devnull
来检查它,并检查结果是否在那里.
At any rate, it is possible that dos2unix
detects that the output isn't a tty anymore and decides to dump the output in it instead (dos2unix
can work from standard input & to standard output). I'd go with that explanation. You could check it by redirecting to a real file instead of os.devnull
and check if the result is there.
但是我会改做一个纯python解决方案(为了安全起见带有备份),该解决方案可移植并且不需要dos2unix
命令(因此它也适用于Windows):
But I would do a pure python solution instead (with a backup for safety), which is portable and doesn't need dos2unix
command (so it works on Windows as well):
with open(file1,"rb") as f:
contents = f.read().replace(b"\r\n",b"\n")
with open(file1+".bak","wb") as f:
f.write(contents)
os.remove(file1)
os.rename(file1+".bak",file1)
完全读取文件速度很快,但可能会阻塞非常大的文件.逐行解决方案也是可行的(仍然使用二进制模式):
reading the file fully is fast, but could choke on really big files. A line-by-line solution is also possible (still using the binary mode):
with open(file1,"rb") as fr, open(file1+".bak","wb") as fw:
for l in fr:
fw.write(l.replace(b"\r\n",b"\n"))
os.remove(file1)
os.rename(file1+".bak",file1)
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