如何写入双工流? [英] How do I write to a duplex stream?

问题描述

假设我有一个超级简单套接字服务器，该服务器在localhost处的端口上接受连接:

Suppose I have a Super Simple Socket Server that accepts connections on a port at localhost:

: server-new ( port -- stream ) f swap <inet4> utf8 <server> accept drop ;

我可以像这样使用它:

IN: scratchpad 1204 server-new 

等待连接.在终端中:

$ curl localhost:1204
_ 

然后等待服务器回复. server-new在堆栈上留下一个duplex-stream.

Which then waits for the server to reply. server-new leaves a duplex-stream on the stack.

T{ duplex-stream
    { in
        T{ decoder
            { stream
                T{ input-port
                    { handle T{ fd { fd 36 } } }
                    { buffer
                        T{ buffer
                            { size 65536 }
                            { ptr ALIEN: 1a44530 }
                        }
                    }
                }
            }
            { code utf8 }
        }
    }
    { out
        T{ encoder
            { stream
                T{ output-port
                    { handle T{ fd { fd 36 } } }
                    { buffer
                        T{ buffer
                            { size 65536 }
                            { ptr ALIEN: 1d42b30 }
                        }
                    }
                }
            }
            { code utf8 }
        }
    }
}

我想向客户端写入一个字符串.我该怎么办?

I want to write a string to the client. How do I do this?

似乎是with-stream之类的答案，但这只是消耗了流对象，而没有任何内容写入我的curl客户端.

It seems like with-stream or something would be the answer, but that just consumes the stream object and nothing gets written to my curl client.

推荐答案

可能在某处缺少冲洗:

[ "hello from Factor" print flush ] with-stream

还请注意，with-stream将在报价结束时关闭流.如果要使其保持打开状态，请使用with-stream*.

Also notice that with-stream will close the stream when the quotation finishes. If you want to leave it open, use with-stream* instead.

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