DateTime :: createFromFormat-PHP格式问题 [英] DateTime::createFromFormat - php format issue

问题描述

PHP-DateTime :: createFromFormat —返回根据指定格式设置的新DateTime对象

PHP - DateTime::createFromFormat — Returns new DateTime object formatted according to the specified format

这有效:

$var = DateTime::createFromFormat('Ymd','20100809')->getTimestamp();

但这失败

在非对象上调用成员函数getTimestamp()

Call to a member function getTimestamp() on a non-object

$var = DateTime::createFromFormat('Y/m/d H:M:S','2010/08/09 07:47:00')->getTimestamp();

推荐答案

在当前情况下，M:S部分是错误的.它必须是i:s.请参见 manual on date().

In the case at hand, the M:S portion is wrong. It needs to be i:s. See the manual on date().

但是，这突出了一个更深层的概念性问题:两个参数中的任何错误输入都将导致致命错误，这对于生产中的应用程序而言是不良行为.

However, this highlights a deeper conceptual problem: An incorrect input in either parameter will lead to a fatal error, which is bad behaviour for an application in production.

摘自 createFromFormat 上的手册:

From the manual on createFromFormat:

失败时返回新的DateTime实例或FALSE.

Returns a new DateTime instance or FALSE on failure.

当呼叫无法根据您的输入建立日期时，将不会返回任何对象.

When the call fails to build a date from your input, no object is returned.

为避免输入错误而造成致命错误，您必须(不幸的是，因为这破坏了很好的链接)，必须首先检查是否成功:

To avoid fatal errors on incorrect inputs, you would (sadly, as this breaks the nice chaining) have to check for success first:

 $var = DateTime::createFromFormat('Y/m/d H:M:S','2010/08/09 07:47:00');

 if ($var instanceof DateTime)
  echo $var->getTimestamp();

这篇关于DateTime :: createFromFormat-PHP格式问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！