PHP-还剩几秒钟? [英] php - seconds to time left?
问题描述
我正在尝试格式化日期,以说还剩下多少秒(以可读格式)还剩下多少时间:
I'm trying to format a date to say how much time is left (in a readable format) from how many seconds are left:
<?php
$seconds = 23414;
$date = new DateTime();
$date->setTime(0, 0, $seconds);
echo $date->format('z G:i:s');
?>
此示例可能会输出类似:344 11:46:45
的内容,这不是我想要的.它应该说类似6 days, 4:12:36
.我在这里什么都没看到: http://www.php.net/manual/zh-CN/function.date.php 可以帮助我正确设置格式.想法?
This example might output something like: 344 11:46:45
which is not what I'd like. It should say something like 6 days, 4:12:36
. I just don't see anything here: http://www.php.net/manual/en/function.date.php that would help me format it correctly. Ideas?
推荐答案
我不知道内置的任何内容,但是编写起来很容易:
I don't know of anything built in, but it's easy enough to write:
function formatSeconds($secondsLeft) {
$minuteInSeconds = 60;
$hourInSeconds = $minuteInSeconds * 60;
$dayInSeconds = $hourInSeconds * 24;
$days = floor($secondsLeft / $dayInSeconds);
$secondsLeft = $secondsLeft % $dayInSeconds;
$hours = floor($secondsLeft / $hourInSeconds);
$secondsLeft = $secondsLeft % $hourInSeconds;
$minutes= floor($secondsLeft / $minuteInSeconds);
$seconds = $secondsLeft % $minuteInSeconds;
$timeComponents = array();
if ($days > 0) {
$timeComponents[] = $days . " day" . ($days > 1 ? "s" : "");
}
if ($hours > 0) {
$timeComponents[] = $hours . " hour" . ($hours > 1 ? "s" : "");
}
if ($minutes > 0) {
$timeComponents[] = $minutes . " minute" . ($minutes > 1 ? "s" : "");
}
if ($seconds > 0) {
$timeComponents[] = $seconds . " second" . ($seconds > 1 ? "s" : "");
}
if (count($timeComponents) > 0) {
$formattedTimeRemaining = implode(", ", $timeComponents);
$formattedTimeRemaining = trim($formattedTimeRemaining);
} else {
$formattedTimeRemaining = "No time remaining.";
}
return $formattedTimeRemaining;
}
我还没有对它进行彻底的测试,但是我确实进行了测试.在使用它之前,您可能需要先对其进行一点测试.
I haven't tested it thoroughly, but the tests I did run worked fine. You might want to test it yourself a bit before using it.
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