Google自定义搜索下一页 [英] Google custom search next page

问题描述

我有以下代码，我不知道如何打印下一页的链接，如何转到下一页?

I have the following code, and i don't know how to print the links of the next page, how to go to the next pages?

#!/usr/bin/python2.4
# -*- coding: utf-8 -*-


import pprint

from apiclient.discovery import build


def main():

    service = build("customsearch", "v1",
                 developerKey="")

    res = service.cse().list(
         q='lectures',
         cx='013036536707430787589:_pqjad5hr1a',
         num=10, #Valid values are integers between 1 and 10, inclusive.
    ).execute() 

    for value in res:
        #print value
        if 'items' in value:
            for results in res[value]:
                print results['formattedUrl'] 

if __name__ == '__main__':
  main()

推荐答案

响应对象包含一个"nextPage"字典.您可以使用它来确定下一个请求的开始索引.像这样:

The response object contains a 'nextPage' dictionary. You can use this to determine the start index of the next request. Like so:

res = service.cse().list(
     q='lectures',
     cx='013036536707430787589:_pqjad5hr1a',
     num=10, #Valid values are integers between 1 and 10, inclusive.
).execute() 

next_response = service.cse().list(
     q='lectures',
     cx='013036536707430787589:_pqjad5hr1a',
     num=10,
     start=res['queries']['nextPage'][0]['startIndex'],
).execute() 

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