我想使用Drive Api从Google Drive下载文件 [英] i want to download file from google drive using Drive Api

问题描述

在此代码中:

file_id = '0BwwA4oUTeiV1UVNwOHItT0xfa2M'
request = drive_service.files().get_media(fileId=file_id)
fh = io.BytesIO()
downloader = MediaIoBaseDownload(fh, request)
done = False
while done is False:
    status, done = downloader.next_chunk()
    print "Download %d%%." % int(status.progress() * 100)

我不知道如何获取file_id，但在上传时却获取了file_id，但是现在我不知道如何获取Google云端硬盘中存在的文件的file_id.

例如如果我上传的文件名为A001002.pdf，该如何获取该文件的文件ID. 网上有些参考资料我听不懂.

链接: files.list

有什么帮助吗?

解决方案

file.list方法包含一个q参数，用于搜索

获取 https://www.googleapis.com/drive/v3/files?q = name +％3D + 'hello'& key = {YOUR_API_KEY}

Python Guess

"""
Shows basic usage of the Drive v3 API.

Creates a Drive v3 API service and prints the names and ids of the last 10 files
the user has access to.
"""
from __future__ import print_function
from apiclient.discovery import build
from httplib2 import Http
from oauth2client import file, client, tools

# Setup the Drive v3 API
SCOPES = 'https://www.googleapis.com/auth/drive.metadata.readonly'
store = file.Storage('credentials.json')
creds = store.get()
if not creds or creds.invalid:
    flow = client.flow_from_clientsecrets('client_secret.json', SCOPES)
    creds = tools.run_flow(flow, store)
service = build('drive', 'v3', http=creds.authorize(Http()))

# Call the Drive v3 API
results = service.files().list(
    pageSize=10, fields="*").execute()
items = results.get('files', [])
if not items:
    print('No files found.')
else:
    print('Files:')
    for item in items:
        print('{0} ({1})'.format(item['name'], item['id']))

请注意，此示例并未显示如何添加其他参数，我仍然在谷歌搜索，但我不是python开发人员，您可能比我更了解如何做到这一点.

in this code :

file_id = '0BwwA4oUTeiV1UVNwOHItT0xfa2M'
request = drive_service.files().get_media(fileId=file_id)
fh = io.BytesIO()
downloader = MediaIoBaseDownload(fh, request)
done = False
while done is False:
    status, done = downloader.next_chunk()
    print "Download %d%%." % int(status.progress() * 100)

I don't know how to get file_id , I was getting file_id while uploading but now I am not able to figure out how to get file_id of the file which is present on Google Drive.

Ex. if my uploaded file has name A001002.pdf , how can i get file id for this file. there is some reference online which i am not able to understand.

link: files.list

any help?

解决方案

The file.list method contains a q paramater which is used for searching

GET https://www.googleapis.com/drive/v3/files?q=name+%3D+'hello'&key={YOUR_API_KEY}

Python Guess

"""
Shows basic usage of the Drive v3 API.

Creates a Drive v3 API service and prints the names and ids of the last 10 files
the user has access to.
"""
from __future__ import print_function
from apiclient.discovery import build
from httplib2 import Http
from oauth2client import file, client, tools

# Setup the Drive v3 API
SCOPES = 'https://www.googleapis.com/auth/drive.metadata.readonly'
store = file.Storage('credentials.json')
creds = store.get()
if not creds or creds.invalid:
    flow = client.flow_from_clientsecrets('client_secret.json', SCOPES)
    creds = tools.run_flow(flow, store)
service = build('drive', 'v3', http=creds.authorize(Http()))

# Call the Drive v3 API
results = service.files().list(
    pageSize=10, fields="*").execute()
items = results.get('files', [])
if not items:
    print('No files found.')
else:
    print('Files:')
    for item in items:
        print('{0} ({1})'.format(item['name'], item['id']))

Note this example does not show how to add the additional parameter i am still Googling that but i am not a python dev you may know more about how to do that than me.

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