使用$ .getjson从外部源请求JSON. 200成功但是在哪里呢? [英] Request for JSON from externel source using $.getjson. 200 success but where is it?

问题描述

我正在尝试从openweathermap获取天气数据.该网址适用于我输入的坐标，在浏览器栏中输入网址时，我可以下载JSON.我正在尝试在我的页面中使用它.当我运行此代码时，在Firebug中，我可以看到HTTP请求获得了200成功代码，但是由于某种原因它没有打印响应.我不能正确使用getJSON吗?

I'm trying to get weather data from openweathermap. This url works with coordinates I put in, and I can download the JSON when I input the url the in the browser bar. I'm trying to get this working in my page. When I run this code, in Firebug I can see the HTTP request got the 200 success code, but it's not printing the response for some reason. Am I not using getJSON properly?

var url = "http://api.openweathermap.org/data/2.5/forecast?lat="+ position.coords.latitude +"&lon=" + position.coords.longitude; 

$.getJSON(url, function(res) {
console.log(res);
});  

推荐答案

您正试图在读取JSONP的函数中读取跨域JSON. 无法跨域JSON读取.

You are trying to read cross domain JSON in a function which reads JSONP. Cross domain JSON reading is not possible.

改为尝试JSONP请求；通过添加回调

Try a JSONP request instead;, by appending a callback

    var url = "http://api.openweathermap.org/data/2.5/forecast?lat=" + 
position.coords.latitude +"&lon=" + position.coords.longitude + "&callback=?" ; 

    $.getJSON(url, function(res) {
    console.log(res);
    });  

JSON响应是这样的: { 'a':22 }

JSON response is like this : { 'a':22 }

JSONP响应类似于: myFunction({'a':22} )，其中myFunction是作为callback

JSONP response is like : myFunction({'a':22} ) , where myFunction was the value passed as callback

jQuery不需要回调函数的名称，但是需要在URL中提及callback，以便它可以将其标识为JSONP请求.

jQuery does not need the name of the callback function, however needs callback to be mentioned in the URL so that it can indentify it as a JSONP request.

JSONP

JSONP

如果URL包含字符串"callback =?" (或类似的定义， 服务器端API)，则该请求将被视为JSONP.见 $ .ajax()中有关jsonp数据类型的讨论，以获取更多详细信息.

If the URL includes the string "callback=?" (or similar, as defined by the server-side API), the request is treated as JSONP instead. See the discussion of the jsonp data type in $.ajax() for more details.

这篇关于使用$ .getjson从外部源请求JSON. 200成功但是在哪里呢?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！