动画另一个元素内的多个元素 [英] Animating multiple elements inside another element
本文介绍了动画另一个元素内的多个元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
所以我有容器,里面有5个div的yui库.这个div是菜单.所以我想做的是,当我将鼠标移到div上方时,只有该动画会向上移动,而当我将鼠标移到其他位置时,它将向下动画.我的js代码同时为所有元素设置动画.
So I have container and inside there is yui library with 5 divs. This divs are menus. So what i want to do is that when I move mouse over div only this one will animate UP and when I move mouse somewhere else it will animate DOWN. My js code animate all elements at same time.
<div class="container">
<div class='yui3-g-r'>
<div class="yui3-u-1-5">
<div class="kvadrat">
<span class="title"><a>Smeri</a></span><br/>
<span class="description">
<ul class="blabla">
<li><a class="link" href="smeri/racunalnistvo_prva/index.html" >Računalništvo</a></li>
<li><a class="link">Strojništvo</a></li>
</ul>
</span>
</div>
</div>
<div class="yui3-u-1-5">
<div class="kvadrat">
<span class="title"><a>Galerija</a></span><br/>
<span class="description">
<ul class="blabla">
<li><a class="link" href="galerija/predstavitev poklicev-nak. center/osnova/index.html">Slike</a></li>
</ul>
</span>
</div>
</div>
我的jQuery代码是这样的:
And my jQuery code is this :
$(".description" ).hide();
$('div.kvadrat').hover(
function () {
$(".description" ).slideDown( "slow" );
},
function () {
$(".description" ).slideUp( "slow" );
}
);
推荐答案
$(".description" ).hide();
$('div.kvadrat').hover(
function () {
$(this).find(".description" ).slideDown( "slow" );
},
function () {
$(this).find(".description" ).slideUp( "slow" );
}
);
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