在PHP语法错误中回显jquery-找不到我的错误 [英] echo jquery in PHP syntax error - can't find my mistake

问题描述

我尝试在PHP中回显jQuery，但是无论执行什么操作都会给我以下错误:

I try to echo out jQuery in PHP but it gives me following error whatever I do:

Parse error: syntax error, unexpected 'foreach' (T_FOREACH), expecting ',' or ';' in /var/www/html/login/application/controllers/sellercentral.php on line 309

代码:

echo '<script>
    $( document ).ready(function() {
         $("#Drafts > tbody:last").append('foreach($this->central as      $key2 => $value2) {
            '<tr> 
            <td><a href='. $value2->Token .'>Edit</a></td>
            <td class=T id='. $value2-    >Token.'>'.htmlentities($value2->Title).'</td>
            </tr>
        '.}.' );

                         });

            </script>';

推荐答案

您不能在echo语句中使用foreach！像这样分解它们:

You can't use a foreach in a echo statement! Just break them up like this:

echo '<script>
      $( document ).ready(function() {
      $("#Drafts > tbody:last").append(';

foreach($this->central as $key2 => $value2) {
    echo '<tr> 
            <td><a href='. $value2->Token .'>Edit</a></td>
            <td class=T id='. $value2-    >Token.'>'.htmlentities($value2->Title).'</td>
          </tr>';
}

echo  ');});</script>';

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