Linq语句，用于连续的两半的无限序列 [英] Linq statement for an infinite sequence of successive halves

问题描述

给出一个起始数字，想象一个连续的两半的无限序列.

Given a starting number, imagine an infinite sequence of its successive halves.

1, 0.5, 0.25, 0.125, ...

(忽略double固有的任何数值不稳定性.)

(Ignore any numerical instabilities inherent in double.)

是否可以在单个表达式中完成而无需编写任何自定义扩展方法或生成器方法?

Can this be done in a single expression without writing any custom extension methods or generator methods?

推荐答案

我不知道单表达式的方式，但是我在这里找到了这个聪明的生成器代码:

I don't know of a single-expression way but I found this clever generator code here: http://csharpindepth.com/articles/Chapter11/StreamingAndIterators.aspx

public static IEnumerable<TSource> Generate<TSource>(TSource start,
                                                  Func<TSource,TSource> step)
{
   TSource current = start;
   while (true)
   {
       yield return current;
       current = step(current);
   }
}

您可以使用它:

foreach (double d in Generate<double>(1, c => c / 2))
{
    ...
}

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