如何加入LiteDb [英] How to Join In LiteDb
问题描述
如何像SQL一样在LiteDb中的两个表之间联接 示例:我有两个表User和ActivityLog
How can i join between two table in LiteDb Like SQL Example : I Have Two table User and ActivityLog
这是模型
public class ActivityLog
{
[BsonId]
public int Id { get; set; }
public string UserId { get; set; }
public string Action { get; set; }
public DateTime ActionDateTime { get; set; }
}
public class User
{
[BsonId]
public int Id { get; set; }
public string UserId { get; set; }
public string UserName { get; set; }
public DateTime LoginDate { get; set; }
}
我需要加入Activity.UserID = User.UserId. 有没有办法像sql一样
I need to join Activity.UserID = User.UserId. Is there any way to join like sql
推荐答案
来自官方文档
LiteDB是一个文档数据库,因此之间没有JOIN 集合.如果您需要在另一个文档中引用一个文档,则可以 可以使用DbRef.可以在 数据库已初始化或在运行查询时或在执行查询后 完成.
LiteDB is a document database, so there is no JOIN between collections. If you need reference a document in another document you can use DbRef. This document reference can be loaded when the database is initialized or when a query is run, or after a query is finished.
就您而言,您可以做类似的事情
In your case, you can do smth like
public class ActivityLog
{
[BsonId]
public int Id { get; set; }
public DbRef<User> User { get; set; }
public string Action { get; set; }
public DateTime ActionDateTime { get; set; }
}
public class User
{
[BsonId]
public int Id { get; set; }
public string UserId { get; set; }
public string UserName { get; set; }
public DateTime LoginDate { get; set; }
}
//usage
// Getting user and activityLog collections
var usersCollection = db.GetCollection<User>("Users");
var activityLogsCollection = db.GetCollection<ActivityLog>("ActivityLogs");
// Creating a new User instance
var user = new User { UserId = 5, ...};
usersCollection.Insert(user);
// Create a instance of ActivityLog and reference to User John
var activityLog = new ActivityLog
{
OrderNumber = 1,
OrderDate = DateTime.Now,
//Add it by DbRef
User = new DbRef<User>(usersCollection, user.UserId)
};
activityLogsCollection.Insert(activityLog)
有关更多详细信息,请参阅文档.
See the documentation for more details.
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