根据Entity Framework Core中的不同列选择所有行 [英] Selecting all rows based on a distinct column in Entity Framework Core
问题描述
我有一个包含一些数据的表,我想使用.NET核心实体框架选择具有唯一日期的行.我想将结果作为唯一行的列表返回.这是代码.
I have a table with some data which I want to select rows with unique dates using the .NET core entity framework. I want to return the results as a list of the unique rows. Here is the code.
public async Task<IEnumerable<Records>> GetUniqueRecordsByDate(int bId)
{
var rowsToReturn = await _context.Records
.Where(b => b.SId == bId)
.Select(d => d.Date)
.Distinct()
.OrderBy(d => d)
.ToListAsync();
return rowsToReturn;
}
我正在尝试应用上面的代码,但出现此错误
I'm trying to apply the above code but I get this error
无法隐式转换类型'System.Collections.Generic.List< System.Linq.IGrouping< System.DateTime,Test.API.Models.Records >>'到'System.Collections.Generic.IEnumerable< Test.API.Models.Record>.存在显式转换(您是否缺少演员表?)
Cannot implicitly convert type 'System.Collections.Generic.List< System.Linq.IGrouping< System.DateTime, Test.API.Models.Records>>'to 'System.Collections.Generic.IEnumerable< Test.API.Models.Record>'. An explicit conversion exists (are you missing a cast?)
还有什么其他方法可以实现我的期望,或者我在代码中缺少某些内容?
Is there any other way that I can implement to get my expectations or I'm I missing something in my code?
推荐答案
首先如下创建DTO
:
public class RecordsByDateDTO
{
public DateTime Date {get; set;}
public List<Record> Records {get; set;}
}
要选择具有唯一日期的行,必须使用.GroupBy
并编写如下的GetUniqueRecordsByDate
方法:
To select rows with unique dates, you have to use .GroupBy
and write your GetUniqueRecordsByDate
method as follows:
public async Task<List<RecordsByDateDTO>> GetUniqueRecordsByDate(int bId)
{
var recordsByDate = await _context.Records.Where(r => r.SId == bId).GroupBy(r => r.Date)
.Select(group => new RecordsByDateDTO
{
Date = group.Key,
Records = group.ToList()
}).OrderBy(r => r. Date).ToListAsync();
return recordsByDate;
}
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