通过udp消息格式将max/msp转换为ruby [英] max/msp to ruby via udp message format

问题描述

我正在尝试为ruby项目使用max/msp构建一个小的GUI 我找不到一种方法来正确转换我从max接收到的数据.

I'm trying to build a little GUI with max/msp for a ruby project I can't find a way to properly convert the data i receive form max.

这是我从ruby的max中收到的消息的几个示例(我先发送2，然后发送1 0 -1 -2):

here is several examples of message that i've received from max in ruby (i've send 2 first then 1 0 -1 -2):

["int\x00,i\x00\x00\x00\x00\x00\x02", ["AF_INET", 53802, "127.0.0.1", "127.0.0.1"]]
["int\x00,i\x00\x00\x00\x00\x00\x01", ["AF_INET", 53802, "127.0.0.1", "127.0.0.1"]]
["int\x00,i\x00\x00\x00\x00\x00\x00", ["AF_INET", 53802, "127.0.0.1", "127.0.0.1"]]
["int\x00,i\x00\x00\xFF\xFF\xFF\xFF", ["AF_INET", 53802, "127.0.0.1", "127.0.0.1"]]
["int\x00,i\x00\x00\xFF\xFF\xFF\xFE", ["AF_INET", 53802, "127.0.0.1", "127.0.0.1"]]

到目前为止，我已经能够通过String#ord或String#unpack将正值转换为整数，但是使用这些方法，负整数给我0值

so far i've been able to convert positive values to integer via String#ord or String#unpack but with those methods negative integers gives me 0 value

推荐答案

您可以轻松地使用#unpack，使用偏移量('@ 8')和32位带符号的bigendian int('l>')

You can easily do it with #unpack, using offset ('@8'), and 32-bit signed bigendian int ('l>')

str.unpack('@8l>')

我不确定字符串的起始部分是什么意思("int \ x00，i \ x00 \ x00")，我只是忽略了它的偏移量.如果有重要数据，则可能需要额外摆弄.

I'm not sure what initial part of string means ("int\x00,i\x00\x00") and I have just ignored it with offset. It might need additional fiddling, if there is any important data.

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