如何在C#中更新srgs语法 [英] how to update srgs grammar in C#

问题描述

我已经创建了用于语义识别的srgs文件，现在我想对myGrammar文件进行审核，现在如何更新my_Grammar.xml文件并在文本框中的项目标签中添加更多城市.有关的帮助材料将不胜感激，并在此先感谢.

I have created srgs file for semantic recognition, now i want to udate myGrammar file,Now How to i update my_Grammar.xml file and add more cities in item tag from textbox. helping material regarding this will be appreciated and thanks in advance.

     <grammar version="1.0" xml:lang="en-US" mode="voice" root="destination" 
            xmlns="http://www.w3.org/2001/06/grammar" tag-format="semantics/1.0">
          <rule id="Source">
               <one-of>
              <item> Karachi </item>
              <item> Lahore </item>
              <item> Abbottabad </item>
 <item> Murree </item>
            </one-of>
          </rule>
 <rule id="destination">
               <one-of>
              <item> Karachi </item>
              <item> Lahore </item>
              <item> Islamabad </item>
            </one-of>
          </rule>
 <rule id="Article">
               <one-of>
              <item> to</item>
             </one-of>
          </rule>
        </grammar>

          SrgsRule SrcRule = new SrgsRule("id_Source");
          SrgsOneOf SrcList = new SrgsOneOf(new string[] { "Lahore","Karachi",Abbottabad ,"Murree"});
          SrcRule.Add(SrcList);

          SrgsRule ArticleRule = new SrgsRule("id_Article");
          SrgsOneOf ArticleList = new SrgsOneOf(new string[] { "to" });
          ArticleRule.Add(ArticleList);

          SrgsRule desRule = new SrgsRule("id_Destination");
          SrgsOneOf desList = new SrgsOneOf(new string[] { "Islamabad","Lahore","Karachi",Abbottabad ,"Murree"});
          desRule.Add(desList);

          SrgsRule rootRule = new SrgsRule("Src_Article_des");
          rootRule.Scope = SrgsRuleScope.Public;

          SrgsRuleRef SrcRef = new SrgsRuleRef(SrcRule, "theSource");
          rootRule.Add(SrcRef);

          SrgsRuleRef ArticleRef = new SrgsRuleRef(ArticleRule, "theArticle");
          rootRule.Add(ArticleRef);

          SrgsRuleRef desRef = new SrgsRuleRef(desRule, "theDestination");
          rootRule.Add(desRef);

          SrgsDocument document = new SrgsDocument();
          document.Rules.Add(new SrgsRule[] { rootRule, SrcRule, ArticleRule, desRule });        
          document.Root = rootRule;
          Grammar g = new Grammar(document, "Src_Article_des");
          sr.LoadGrammar(g);
          System.Xml.XmlWriter writer =
            System.Xml.XmlWriter.Create("c:\\test\\myGrammar.xml");
          document.WriteSrgs(writer);
          writer.Close();

推荐答案

  public void AddItemToRule(string inFile, string outFile, string ruleId, string itemVal)
        {
            XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.Load(inFile); // loads xml file
            if (AddItemToRule(xmlDoc, ruleId, item))
            {
                xmlDoc.Save(outFile);
                MessageBox.Show(@"Inserted Successfully");
            }
        }

        public bool AddItemToRule(XmlDocument xmlDoc, string ruleId, string itemVal)
        {
            string ns = "http://www.w3.org/2001/06/grammar";
            XmlNamespaceManager nsMgr = new XmlNamespaceManager(xmlDoc.NameTable);
            nsMgr.AddNamespace("g", ns);
            System.Diagnostics.Debug.WriteLine(nsMgr.DefaultNamespace);
            XmlNode foundNode = xmlDoc.SelectSingleNode("//g:rule[@id='" + ruleId + "']/g:one-of", nsMgr);
            if (foundNode != null)
            {
                XmlElement eleItem = xmlDoc.CreateElement("item");


                var text = xmlDoc.CreateTextNode(item);
                eleItem.AppendChild(text);

                foundNode.AppendChild(eleItem);
                return true;
            }
            return false;
        }

     AddItemToRule(path, path, "id_Source", itemValue);
     AddItemToRule(path, path, "id_Article", itemValue);
     AddItemToRule(path, path, "id_Destination", itemValue);

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