使用嵌套字典对URL进行编码 [英] Encode URL with nested dictionaries

问题描述

我使用的API在请求的正文中不接受JSON.它使用x-www-form-urlencoded.

I am using an API that doesn't accept JSON in the requests' bodies. It uses x-www-form-urlencoded.

因此，如果我必须发送此dict:

Thus, if I have to send this dict:

{
    'a': 1,
    'b': 2,
    'c': {
        'k': 3,
        'v': 4,
        'l': {
            'p': 5,
            'q': 6,
        },
    },
}

必须这样编码:

a=1
b=2
c[k]=3
c[v]=4
c[l][p]=5
c[l][q]=6

但是，urllib.parse.urlencode不会以这种方式解析dict.相反，它将直接对c内容进行编码并将其放入(c5)中.

However, urllib.parse.urlencode won't parse the dict this way. Instead it's going to encode c content literally and put within it (c={encodeddict}).

我尝试自己实现一些编码器，但是我无法处理多个嵌套的dicts.我只设法编码1级dicts(如c[k]=3)，但没有递归编码到最后一级(例如，c[l][p]=5).

I tried to implement some encoder like this by myself, but I couldn't get to deal with multiple nested dicts. I only managed to encode 1-level dicts (like c[k]=3), but not recursively to the last level (c[l][p]=5, for example).

在Python 3中实现这种编码的最佳方法是什么?

What is the best way to achieve this kind of encoding in Python 3?

推荐答案

使用递归:

将您的字典传递到dict_to_urlencoded()，它将根据您的描述返回编码格式的字符串. (未排序)

pass your dict to dict_to_urlencoded(), and it'll return encoded format string based on your description. (unsorted)

def dict_to_urlencoded(d):
    return kv_translation(d, "", "")


def kv_translation(d, line, final_str):
    for key in d:
        key_str = key if not line else "[{}]".format(key)
        if type(d[key]) is not dict:
            final_str = "{}{}{}={}\n".format(final_str, line, key_str, d[key])
        else:
            final_str = kv_translation(d[key], line + key_str, final_str)
    return final_str

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