使用python正确编码文件路径 [英] Encode file path properly using python

问题描述

我正在尝试通过从字典中获取路径来打开文件.其中一些文件名带有逗号(，)和其他此类字符，当使用这些字符时会出现找不到此类文件错误"

I am trying to open files by getting the path from a dictionary. Some of the file names have commas (,) and other such characters which when used give a "no such file found error"

例如，以下文件路径将不会打开:foo,%20bar.mp3

For instance the following file path will not open: foo,%20bar.mp3

如果存在像逗号这样的字符，则应将其编码为:foo%2C%20bar.mp3

If characters like commas exist then it should be encoded as : foo%2C%20bar.mp3

谁能告诉我该怎么做?

推荐答案

您可能需要pathname2url

Python 2.x(文档)

Python 2.x (docs)

>>> from urllib import pathname2url 
>>> pathname2url('foo, bar.mp3')
'foo%2C%20bar.mp3'

Python 3.x(文档 )

Python 3.x (docs)

>>> from urllib.request import pathname2url
>>> pathname2url('foo, bar.mp3')
'foo%2C%20bar.mp3'

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