如何使用Python正式插入URL空间(％20)? [英] How to formally insert URL space (%20) using Python?

问题描述

在ebay中输入多词搜索词时，结果URL看起来像(例如"demarini cf5 cf12"):

When a mutli-word search term is entered in ebay, the resultant URL looks something like (for example "demarini cf5 cf12"):

http://www.ebay.com/sch/i.html?_from=R40&_sacat=0&_nkw=demarini%20cf5%20cfc12

我希望用Python构造此URL，以便可以直接访问它.因此，是串联基本URL的情况:

I wish to construct this URL in Python so it can be accessed directly. So it's case of concatenating the base URL:

http://www.ebay.com/sch/i.html?_from=R40&_sacat=0&_nkw=

...以及搜索词.现在.因此，我将%20明确地添加到空格中:

... with the search term. Right now. I am adding the %20 for the spaces explicately thus:

baseUrl = 'http://www.ebay.com/sch/i.html?_from=R40&_sacat=0&_nkw='
searchTerm = 'demarini cf5 cf12'
searchTerm = ('%20').join(searchTerm.split(' '))
finalUrl = baseUrl + searchTerm

在Python中执行此操作的更正式的方法是什么?我相信这类任务的名称是URL编码吗?

What is a more formal way of doing this in Python? I believe the name for this sort of task is URL encoding?

推荐答案

简单易用的urllib库 导入urllib

It's simple use urllib library import urllib

finalurl = baseUrl + urllib.quote(searchterm)

您可以使用quote_plus()添加％20的+ insted 撤消此用途

you can use quote_plus() to add + insted of %20 to undo this use

urllib.unquote(str)

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