如何使用Python获取GeoJSON多边形的面积 [英] How do I get the area of a GeoJSON polygon with Python

问题描述

我有GeoJSON

{
  "type": "FeatureCollection",
  "features": [
    {
      "type": "Feature",
      "properties": {},
      "geometry": {
        "type": "Polygon",
        "coordinates": [
          [[13.65374516425911, 52.38533382814119], [13.65239769133293, 52.38675829106993], [13.64970274383571, 52.38675829106993], [13.64835527090953, 52.38533382814119], [13.64970274383571, 52.38390931824483], [13.65239769133293, 52.38390931824483], [13.65374516425911, 52.38533382814119]]
        ]
      }
    }
  ]
}

http://geojson.io 显示为

我想用Python计算其面积(87106.33m ^ 2).我该怎么办?

I would like to calculate its area (87106.33m^2) with Python. How do I do that?

# core modules
from functools import partial

# 3rd pary modules
from shapely.geometry import Polygon
from shapely.ops import transform
import pyproj

l = [[13.65374516425911, 52.38533382814119, 0.0], [13.65239769133293, 52.38675829106993, 0.0], [13.64970274383571, 52.38675829106993, 0.0], [13.64835527090953, 52.38533382814119, 0.0], [13.64970274383571, 52.38390931824483, 0.0], [13.65239769133293, 52.38390931824483, 0.0], [13.65374516425911, 52.38533382814119, 0.0]]
polygon = Polygon(l)

print(polygon.area)
proj = partial(pyproj.transform, pyproj.Proj(init='epsg:4326'),
                   pyproj.Proj(init='epsg:3857'))
print(transform(proj, polygon).area)

它给出了1.1516745933889345e-05和233827.03300877335-第一个没有意义，但是我该如何解决第二个问题呢? (我不知道如何设置pyproj.Proj init参数)

It gives 1.1516745933889345e-05 and 233827.03300877335 - that the first one doesn't make any sense was expected, but how do I fix the second one? (I have no idea how to set the pyproj.Proj init parameter)

我想epsg:4326是WGS84(源) ，但对于 epsg:3857 我不确定.

I guess epsg:4326 makes sense at it is WGS84 (source), but for epsg:3857 I'm uncertain.

以下内容更近了:

# core modules
from functools import partial

# 3rd pary modules
import pyproj
from shapely.geometry import Polygon
import shapely.ops as ops

l = [[13.65374516425911, 52.38533382814119, 0],
     [13.65239769133293, 52.38675829106993, 0],
     [13.64970274383571, 52.38675829106993, 0],
     [13.64835527090953, 52.38533382814119, 0],
     [13.64970274383571, 52.38390931824483, 0],
     [13.65239769133293, 52.38390931824483, 0],
     [13.65374516425911, 52.38533382814119, 0]]
polygon = Polygon(l)

print(polygon.area)
geom_area = ops.transform(
    partial(
        pyproj.transform,
        pyproj.Proj(init='EPSG:4326'),
        pyproj.Proj(
            proj='aea',
            lat1=polygon.bounds[1],
            lat2=polygon.bounds[3])),
    polygon)
print(geom_area.area)

它给出了87254.7m ^ 2-与geojson.io所说的仍然相差148m ^ 2.为什么会这样呢?

it gives 87254.7m^2 - that is still 148m^2 different from what geojson.io says. Why is that the case?

推荐答案

看起来geojson.io不在像您一样将球形坐标投影到平面上之后计算面积，而是使用一种特定的算法来计算面积直接从WGS84坐标在球体表面上绘制多边形的角度.如果要重新创建它，可以在此处找到源代码. >.

It looks like geojson.io is not calculating the area after projecting the spherical coordinates onto a plane like you are, but rather using a specific algorithm for calculating the area of a polygon on the surface of a sphere, directly from the WGS84 coordinates. If you want to recreate it you can find the source code here.

如果您乐意将坐标投影到平面系统以计算面积，因为它对于您的用例而言足够准确，那么您可以尝试使用

If you are happy to carry on projecting the coordinates to a flat system to calculate the area, since it's good enough accuracy for your use case, then you might trying using this projection for Germany instead. E.g:

from osgeo import ogr
from osgeo import osr

source = osr.SpatialReference()
source.ImportFromEPSG(4326)

target = osr.SpatialReference()
target.ImportFromEPSG(5243)

transform = osr.CoordinateTransformation(source, target)

poly = ogr.CreateGeometryFromJson(str(geoJSON['features'][0]['geometry']))
poly.Transform(transform)
poly.GetArea()

返回87127.2534625642

这篇关于如何使用Python获取GeoJSON多边形的面积的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！