Apache URL重写UUID v1 [英] Apache URL rewrite UUID v1

问题描述

如何重写36个字符的 v1 UUID 精确地使用RewriteRule进行最大检查?

How do you rewrite a 36 character v1 UUID precisely with maximal-checking using RewriteRule?

UUID() returns a value that conforms to UUID version 1 as described in RFC 4122. The value is a 128-bit number represented as a utf8 string of five hexadecimal numbers in aaaaaaaa-bbbb-cccc-dddd-eeeeeeeeeeee format:

请提供比这更好的东西: RewriteRule ^([A-z0-9\-]{36})$ index.php?uuid=$1 [L,QSA]

Please give something better than this: RewriteRule ^([A-z0-9\-]{36})$ index.php?uuid=$1 [L,QSA]

推荐答案

您可以尝试:

^[a-fA-F0-9]{8}-(?:[a-fA-F0-9]{4}-){3}[a-fA-F0-9]{12}$

上述正则表达式的解释:

• ^, $ -分别代表行的开始和结束.
• [a-fA-F0-9]{8} -根据文档； 作为包含五个十六进制数字的utf8字符串；因此最好只允许使用十六进制字符.所以; -之前的第一个字符串是8个字符的十六进制值.
• (?:[a-fA-F0-9]{4}-){3} -表示一个非捕获组，匹配4个十六进制字符，后跟一个-，整个模式精确地重复3次.
• [a-fA-F0-9]{12} -精确表示十六进制字符12次.
• $0 -对于匹配部分，您可以使用第0个捕获组，因为没有特殊捕获.

• ^, $ - Represents start and end of the line respectively.
• [a-fA-F0-9]{8} - According to the docs; as a utf8 string of five hexadecimal numbers; so it is good to allow only hex characters. Therefore; first string before - is 8 characters long hex value.
• (?:[a-fA-F0-9]{4}-){3} - Represents a non-capturing group matching hex characters 4 times followed by a - and the whole pattern repeats exactly 3 times.
• [a-fA-F0-9]{12} - Represents hex characters exactly 12 times.
• $0 - For the matching part you may use 0th captured group since there is no special capturing.

Regex演示

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