如何使用Scala分派获取301重定向中返回的URL? [英] How do I use Scala dispatch to get the URL returned in a 301 redirect?

问题描述

我正在使用Scala dispatch HTTP库，版本0.10.1.我向返回HTTP 301(永久重定向)的URL发出请求.例如， http://wikipedia.com 返回301，该重定向到

I am using Scala dispatch HTTP library, version 0.10.1. I make a request to a URL that returns an HTTP 301, permanent redirect. For example, http://wikipedia.com returns a 301 that redirects to http://www.wikipedia.org/. How do I do I use dispatch to get the redirected URL?

在学习本教程之后，这就是我所做的.

Following the tutorial, here's what I've done.

import dispatch._, Defaults._
val svc = url("http://wikipedia.com")
val r = Http(svc OK as.String)
r()

这将引发意外的响应状态:301"异常.大概我需要查询重定向URL的r值，或者在其定义中指定OK以外的其他参数，但是我无法从文档中找出要做什么.

This throws a "Unexpected response status: 301" exception. Presumably I need to either query the r value for the redirected URL, or maybe specify some argument other than OK in its definition, but I can't figure out what to do from the documentation.

推荐答案

配置基础asyncClient进行重定向:

Configure the underlying asyncClient to follow redirects:

val r = Http.configure(_ setFollowRedirects true)(svc OK as.String)

要获取重定向的URL，请执行以下操作:

To get the redirected URL:

val svc = url("http://wikipedia.com/")
val r = Http(svc > (x => x))
val res = r()

println(res.getHeader("Location"))

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