试图从字符串中提取复数 [英] trying to extract complex numbers from strings

问题描述

我正在尝试从文本文件中提取两列数字.第一列是数字的实数部分，第二列是虚数部分.我设法从文件中提取数字列表作为字符串，但是我不知道如何将字符串分成两部分.我试图使用sscanf函数，但还没有工作.困难的部分是数字既可以是正数也可以是负数，因此我不能在strtok函数的定界符中使用+和-，因为它将删除负数.我被困了几天，所以任何建议将不胜感激.提前致谢.这是我在sscanf行上出错的代码.

I am attempting to extract two columns of numbers from a text file. first column is the real part of the number and the second in the imaginary part. I managed to extract the list of numbers from the file as strings but I don't know how to separate the strings into two parts. I have attempted to use the sscanf function but just hasnt worked. The difficult part is the numbers can be both positive and negative therefore I cant use + and - in the delimiter of the strtok function since it will remove the negatives. Iv been stuck for a few days so any suggestions would be appreciated. Thanks in advance. Here is the code I worte which errors at the sscanf line.

        #include <stdio.h>
        #include <stdlib.h>
        #include <string.h>
        #include <complex.h>

        char array[35]= "[[[1+1i -4+100i 45-234i -56-78i]]]";
        char *arrayp[35];
        int count,n,i,j;
        double complex z1;
        double real = 0;
        double imaginary = 0;

        int main()
        {
            arrayp[0] = strtok(array," []");
            n=1;
            while (arrayp[n-1]!=NULL)
            {
               arrayp[n] = strtok(NULL, " []");
               n++;
            }
        // up to this point it has been tested to work. the remaining code is very 
        // sloppy since I have tried 8 different things and have quickly written one of 
        // the options tried.    

            for(j=0;j<n;j++)
            {
                if (strchr(*arrayp, '+'))
                {
                    sscanf(arrayp[j],"%f+%fi", real, imaginary);
                }
                else if(arrayp string has equal to more than 1 '-')
                {
                     sscanf(arrayp[j],"%f%fi", real, imaginary);
                }
            }
        }

输出应该是这样的:
0 0
-4 100
45 -234
-56 -78

The output should be something like this:
0 0
-4 100
45 -234
-56 -78

我注意到有一些错误，例如尝试在strchr中搜索* arrayp，但是它的指针我不知道如何将指针转换为字符串，因此我可以将其放入此文件中.谢谢您的事先帮助和努力.

I noticed there are mistakes such are trying to search *arrayp in strchr but its a pointer I dont know how to convert a pointer into a string so i can put it into this file. Thank you for the help and effort in advance.

推荐答案

到目前为止很好，但是在

So far so good but in

sscanf(arrayp[j],"%f%fi", real, imaginary);

有两个错误.首先，scanf函数族需要%lf作为double目标.

there are two errors. Firstly the scanf function family needs %lf for a double target.

第二，它需要目标的地址，所以

Secondly, it needs the address of the target, so

sscanf(arrayp[j], "%lf%lfi", &real, &imaginary);

此外，我不明白为什么需要首先构建一个字符串指针数组-仅检查strtok产生的每个非NULL令牌指针.

Also, I don't see why you need to build an array of string pointers first - just examine every non-NULL token pointer that strtok produces.

编辑:这是一个小测试程序.

this is a little test program.

#include <stdio.h>
#include <string.h>

int main ()
{
    double r, i;
    char array[]= "[[[1+1i -4+100i 45-234i -56-78i]]]";
    char *tok;
    tok = strtok(array, " []");
    while(tok) {
        sscanf(tok, "%lf%lfi", &r, &i);
        printf("%.0f %.0fi\n", r, i);
        tok = strtok(NULL, " []");
    }
    return 0;
}

程序输出:

1 1i
-4 100i
45 -234i
-56 -78i

程序应更加严格，并检查sscanf中的返回值.

The program should be more rigorous and check the return value from sscanf.

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