password_verify不验证哈希 [英] password_verify doesn't verify hash
问题描述
我通过password_hash对插入的密码进行哈希处理.我通过使用password_verify来验证它们.
I hash my inserted passwords via password_hash. I verify them by using password_verify.
但是,当我在数据库中插入一个哈希密码并尝试对其进行验证时,两个输出总是彼此不同的.
However when I insert a hashed password in my database and I try to verify it, both outputs always differ from eachother.
我的页面如下,
main_login.php(窗体):
main_login.php (form):
<?php include 'header.php';?>
<body>
<form role="form" method="post" action="login.php">
<div class="form-group">
<label for="usrname">Username:</label>
<input type="text" class="form-control" name="usrname" placeholder="Enter username">
</div>
<div class="form-group">
<label for="passwrd">Password:</label>
</div>
<input type="password" class="form-control" name="passwrd" placeholder="Enter password">
<br>
<input type="checkbox">Remember Me
<br>
<br>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</body>
</html>
login.php(处理程序):
login.php (handler):
<?php
include 'vars.php';
include 'header.php';
$sql="SELECT * FROM members WHERE usrname='$usrname'";
$result=mysqli_query($con,$sql);
$count=mysqli_num_rows($result);
$row=mysqli_fetch_row($result);
$verify=password_verify($hash,$row[2]);
if($verify){
$_SESSION["usrname"]=$usrname;
echo "Correct";
}
else {
echo "user: " . $usrname. "<br>";
echo "pass: " . $hash. "<br>";
echo "db: " . $row[2]."<br>";
echo "Wrong Username or Password";
}
?>
vars.php:
<?php
$h='localhost';$u='caelin';$p='****';$d='ombouwnh';
$con=mysqli_connect($h,$u,$p,$d);
$usrname=$_POST['usrname'];
$passwrd=$_POST['passwrd'];
$hash=password_hash($passwrd, PASSWORD_DEFAULT);
?>
当我尝试使用用户名"caca"和密码"caca"登录时,每次重试时,两者都会得到不同的输出. 我在stackoverflow上找不到这个特殊的问题.
when i try to login using username 'caca' and password 'caca' I get a different output for both, everytime i retry. I can't find this particular problem on stackoverflow.
TIA
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推荐答案
函数password_verify();
具有两个参数.非哈希输入,以及与其进行比较的存储哈希.它会自动对未哈希的输入进行哈希处理,以将其与存储的版本进行比较.因此,您的初始代码是重新哈希一个已经哈希的密码.应该看起来像这样:
The function password_verify();
takes two parameters; a non-hashed input, and a stored hash to compare it to. It hashes the non-hashed input automatically to compared it to the stored version. So your initial code was re-hashing an already hashed password. Should look like this:
$verify=password_verify($_POST['passwrd'],$row[2]);
if($verify){
$_SESSION["usrname"]=$usrname;
echo "Correct";
}
else {
echo "user: " . $usrname. "<br>";
echo "pass: " . $hash. "<br>";
echo "db: " . $row[2]."<br>";
echo "Wrong Username or Password";
}
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