错误C4996:'scanf':该函数或变量在C编程中可能不安全 [英] error C4996: 'scanf': This function or variable may be unsafe in c programming

问题描述

我创建了一个小应用程序，通过使用带有参数的用户定义函数来查找最大数目.当我运行它时，它显示此消息

I have created a small application to find max number by using user-defined function with parameter. When I run it, it shows this message

错误1错误C4996:'scanf':该函数或变量可能不安全. 考虑改用scanf_s.要禁用弃用，请使用 _CRT_SECURE_NO_WARNINGS.有关详细信息，请参见在线帮助.

Error 1 error C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details.

该如何解决?

这是我的代码

#include<stdio.h>

void findtwonumber(void);
void findthreenumber(void);

int main() {
    int n;
    printf("Fine Maximum of two number\n");
    printf("Fine Maximum of three number\n");

    printf("Choose one:");
    scanf("%d", &n);
    if (n == 1)
    {
        findtwonumber();
    }
    else if (n == 2)
    {
        findthreenumber();
    }
    return 0;
}

void findtwonumber(void)
{
    int a, b, max;
    printf("Enter a:");
    scanf("%d", &a);
    printf("Enter b:");
    scanf("%d", &b);
    if (a>b)
        max = a;
    else
        max = b;
    printf("The max is=%d", max);
}

void findthreenumber(void)
{
    int a, b, c, max;
    printf("Enter a:");
    scanf("%d", &a);
    printf("Enter b:");
    scanf("%d", &b);
    printf("Enter c:");
    scanf("%d", &c);
    if (a>b)
        max = a;
    else if (b>c)
        max = b;
    else if (c>a)
        max = c;
    printf("The max is=%d", max);
}

推荐答案

听起来像只是编译器警告.

It sounds like it's just a compiler warning.

使用scanf_s可以防止缓冲区溢出.
请参阅: http://code.wikia.com/wiki/Scanf_s

Usage of scanf_s prevents possible buffer overflow.
See: http://code.wikia.com/wiki/Scanf_s

关于为什么scanf可能是危险的很好的解释: scanf的缺点

Good explanation as to why scanf can be dangerous: Disadvantages of scanf

因此，按照建议，您可以尝试将scanf替换为scanf_s或禁用编译器警告.

So as suggested, you can try replacing scanf with scanf_s or disable the compiler warning.

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