循环属性以创建库存变化 [英] loop on attributes to create inventory variations

问题描述

例如，我具有以下属性数组:

I have this array of attributes for example:

Array
(

    [0] => Array
        (
            [id] => 20
            [title] => Brown
            [parent_id] => 1
            [parent_title] => Color
            [isMultiple] => 1
        )

    [1] => Array
        (
            [id] => 21
            [title] => Cream
            [parent_id] => 1
            [parent_title] => Color
            [isMultiple] => 1
        )

    [2] => Array
        (
            [id] => 61
            [title] => S
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

    [3] => Array
        (
            [id] => 62
            [title] => M
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

    [4] => Array
        (
            [id] => 63
            [title] => L
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

)

从这个数组中我们可以了解到，我们有6种不同的广告资源:

from this array we can understand that we have 6 variations of inventory:

1 | Brown | S
2 | Brown | M
3 | Brown | L
4 | Cream | S
5 | Cream | M
6 | Cream | L

1. 像上面的示例一样，循环遍历此数组以创建6个变体的另一个数组的正确方法是什么.

1. What is the correct way to loop over this array to create another array of the 6 variations like in the above example.

让我们假设我在数组中还有另外2个attrs，如下所示:

let's assume that I have another 2 attrs in the array like this:

[5] => Array
    (
        [id] => 64
        [title] => Cotton
        [parent_id] => 3
        [parent_title] => Metiral
        [isMultiple] => 1
    )

[6] => Array
    (
        [id] => 65
        [title] => Wool
        [parent_id] => 3
        [parent_title] => Metiral
        [isMultiple] => 1
    )

如何在此数组上循环创建类似这样的变体:

How I can loop on this array to create variations like these:

1 | Brown | S | wool
2 | Brown | S | cotton
3 | Brown | M | wool
4 | Brown | M | cotton
5 | Brown | L | wool
6 | Brown | L | cotton
7 | Cream | S | wool
8 | Cream | S | cotton
9 | Cream | M | wool
10 | Cream| M | cotton
11 | Cream| L | wool
12 | Cream| L | cotton

提前谢谢！

推荐答案

好，我找到了解决方法:

OK I found the solution:

A.正确，我对所有属性都做了一个关联数组:

A. right, I made an associative arrays of all my attributes:

数组 (

[0] => Array
    (
        [0] => 20
        [1] => 21
    )

[1] => Array
    (
        [0] => 61
        [1] => 62
        [2] => 63
    )

)

B.然后我递归地创建整个可能的变体:

B. then I recursively create the whole possible variations:

function buildVariants($arrays, $i = 0) {
if (!isset($arrays[$i])) {
    return array();
}
if ($i == count($arrays) - 1) {
    return $arrays[$i];
}

// get combinations from subsequent arrays
$tmp = $this->buildVariants($arrays, $i + 1);

$result = array();

// concat each array from tmp with each element from $arrays[$i]
foreach ($arrays[$i] as $v) {
    foreach ($tmp as $t) {
    $result[] = is_array($t) ? array_merge(array($v), $t) : array($v, $t);
    }
}

return $result;
}    

C.然后将其添加到这种结构的表中:

C. then I add it to tables in this structure:

请参阅表stru

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