在Python中使用Selenium单击/选择单选按钮 [英] Using Selenium in Python to click/select a radio button

问题描述

我正在尝试从3个按钮的列表中进行选择，但是找不到选择它们的方法.下面是我正在使用的HTML.

I am trying to select from a list of 3 buttons, but can't find a way to select them. Below is the HTML I am working with.

<input name="pollQuestion" type="radio" value="SRF"> 
    <font face="arial,sans-serif" size="-1">ChoiceOne</font><br />
<input name="pollQuestion" type="radio" value="COM">
    <font face="arial,sans-serif" size="-1">ChoiceTwo</font><br />
<input name="pollQuestion" type="radio" value="MOT">
    <font face="arial,sans-serif" size="-1">ChoiceThree</font>

我可以使用以下代码找到它:

I can find it by using the following code:

for i in browser.find_elements_by_xpath("//*[@type='radio']"):
     print i.get_attribute("value")

此输出:SRF，COM，MOT

This outputs: SRF,COM,MOT

但是我想选择ChoiceOne. (单击它)我该怎么做?

But I would like to select ChoiceOne. (To click it) How do I do this?

推荐答案

使用CSS选择器或XPath直接通过value属性进行选择，然后单击它.

Use CSS Selector or XPath to select by value attribute directly, then click it.

browser.find_element_by_css_selector("input[type='radio'][value='SRF']").click()
# browser.find_element_by_xpath(".//input[@type='radio' and @value='SRF']").click()

更正(但是OP应该学习如何在文档中查找)

Corrections (but OP should learn how to look up in documentation)

• 在Python绑定中，find_elements_by_css不存在，称为find_elements_by_css_selector.一个人应该能够查看异常消息并回顾文档此处是API文档.之所以使用后者，是因为我复制了您的代码，但我不应该这样做.

• In Python binding, find_elements_by_css doesn't exist, it's called find_elements_by_css_selector. One should be able to look at the exception message and look back into documentation here and figure out why.
• Notice the difference between find_element_by_css_selector and find_elements_by_css_selector? The first one finds the first matching element, the second one finds a list, so you need to use [0] to index. Here is the API documentation. The reason why I use the latter, is because I copied your code, which I shouldn't.

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