如何通过Python使用Selenium来定位按钮元素 [英] How to locate the button element using Selenium through Python
问题描述
我正在尝试查找元素，然后单击按钮不立即".我已经尝试过使用xs的css_selector，但是我根本找不到正确的方法.
I'm trying to find the element and click for the button "Not Now". I've tried with with css_selector, xpath, but I"m unable at all to find the proper way.
HTML:
推荐答案
要定位并在元素上以不立即显示作为文本的click()，您可以使用以下
To locate and click() on the element with text as Not Now you can use the following Locator Strategy:
-
使用
xpath:
driver.find_element_by_xpath("//button[text()='Not Now']").click()
但是，该元素对我而言似乎是动态的，因此您需要为element_to_be_clickable()引入 WebDriverWait ，并且可以使用以下任意一种 Locator Strategy :
However, the element looks dynamic to me so you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategy:
-
使用
XPATH:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//div//button[text()='Not Now']"))).click()
注意:您必须添加以下导入:
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
您可以在以下位置找到一些相关的讨论:
You can find a couple of relevant discussions in:
- What does contains(., 'some text') refers to within xpath used in Selenium
- While fetching all links,Ignore logout link from the loop and continue navigation in selenium java
- How does dot(.) in xpath to take multiple form in identifying an element and matching a text
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