如何在登录的slenium中执行类，而不是打开新的chrome实例? [英] How to execute class in logged in slenium instead of opening new chrome instance?

问题描述

from selenium import webdriver
from time import sleep
filename = "log.txt"
myfile = open(filename, 'w')

class Search(object):
    def __init__(self):
        self.driver = webdriver.Chrome('chromedriver.exe') 

        # "This will open a new chrome instance without being logged in to the site"

        self.driver.get("Site2")
        sleep(2)
        self.driver.find_element_by_xpath("/html/body/div[1]/div[4]/div/div/div[3]/div/div/div[2]/div[2]/div[2]/div/div[4]/div[1]/div[2]/div[1]/a").click()
        sleep(2)
        Texto = self.driver.find_element_by_xpath("/html/body/div[1]/div[4]/div/div/div[4]/div/div/div[1]/div[3]/div/article[1]/div/div[2]/div/div/div/article/div[1]").text
        print(Texto)
        myfile.write(Texto)
        myfile.close()
        sleep(10)
        import re
        Id = re.compile('[0-9]{9}')
        Id2 = re.compile('[0-9]{4}')
        DobMonth = re.compile('[0-9]{2}')
        DobYear = re.compile('[0-9]{2}')
        if Id.match(Texto) and Id2.match(Texto) and DobMonth.match(Texto) and DobYear.match(Texto):
            print ("Matches")
        else:
            print("Not match")
            sleep (20)
            Search()

class BasicBot(object):
    def __init__(self, username, pw):
        self.driver = webdriver.Chrome('chromedriver.exe')
        self.driver.get("site1")
        sleep(2)
        self.driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/div/div[1]/a[1]/span").click()
        sleep(2)
        self.driver.find_element_by_xpath("//input[@name=\"login\"]")\
        .send_keys(username)
        self.driver.find_element_by_xpath("//input[@name=\"password\"]")\
        .send_keys(pw)
        self.driver.find_element_by_xpath('/html/body/div[4]/div/div[2]/div/form/div[1]/dl/dd/div/div[2]/button').click()
        sleep(2)
        Search()


BasicBot('username',"password")

因此该脚本运行BasicBot(usr,psswd)登录到该站点，并且应该在登录时转到另一个站点，然后搜索X post是否符合给定的条件，如果符合，就是这样，否则应该刷新站点并再次检查.

So the script runs BasicBot(usr,psswd) logs in to the site, and is supposed to go to a different site while logged in, then searches if X post matches the criteria given, if it does that's it if it does not, I should refresh the site and check again.

推荐答案

在Search类中，首先创建一个新的chromedriver实例:self.driver = webdriver.Chrome('chromedriver.exe')，这就是为什么它会打开另一个具有新状态的窗口的原因.

In the Search class, you start with creating a new chromedriver instance: self.driver = webdriver.Chrome('chromedriver.exe'), this is why it opens another window with a fresh state.

相反，将您的Search类修改为

Instead, modify your Search class to

1. 采用现有的webdriver实例.
2. 使用脚本window.open而不是get打开新窗口:

1. take an existing instance of webdriver.
2. open a new window by using script window.open instead of get:

class Search:
    def __init__(self, driver):
        self.driver = driver
        # Open a new window
        self.driver.execute_script("window.open('https://site2')")
        sleep(2) # visually check to make sure it opened

        # Switch to new window
        self.driver.switch_to.window(self.driver.window_handles[-1])
        # After this you can start doing self.driver.find_element_by_xpath and the rest

在BasicBot类中，修改最后一行以传递驱动程序:

In the class BasicBot, modify the last line to pass the driver:

Search(self.driver)

最后，您可以使用刷新"来刷新您的站点2:

Lastly, you can use refresh to refresh your site2:

else:
    print("Not match")
    sleep(20)
    self.driver.refresh()

希望，它会有所帮助.祝你好运！

Hope, it helps. Good luck!

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