InvalidSelectorError:无效选择器:无法使用xpath表达式定位元素 [英] InvalidSelectorError: invalid selector: Unable to locate an element with the xpath expression

问题描述

以下是html代码段元素

Following is html snippet element

<a ng-click="nodes.setViewType('tiles',true)">
 <span class="fa fa-check Tick-Inactive" ng-class="nodes.viewType == 'tiles'? 'Tick-Active':'Tick-Inactive'" style=""></span>
                Tile View
</a>

尝试使用Java脚本转义符在定位器中使用ng-click或ng-class.但显示选择器无效或非法

Trying to use ng-click or ng-class in locators using java script escape characters. But it showing invalid or illegal selector was specified

element(by.xpath("//a[contains(@ng-click,'nodes.setViewType(\'tiles\',true)')]"));

element(by.css("span[ng-class^=nodes.viewType == \'tiles\']"));

element(by.xpath("//a[contains(@ng-click,'nodes.setViewType%28%27tiles%27%2Ctrue%29')]"));

推荐答案

此错误消息...

invalid or illegal selector was specified

...表示您构建的定位器策略不是有效的定位器.

...implies that the Locator Strategy you have constructed was not a valid locator.

要找到文本为 Tile View 的元素，可以使用以下 xpath :

To locate the element with text as Tile View you can use the following xpath :

"//a[@ng-click=\"nodes.setViewType('tiles',true)\"]"

注意:由于该元素是与 Angular 进行交互的元素，因此必须诱使该元素可点击的服务生.

Note : As the element is an Angular element to interact with it you have to induce a waiter for the element to be clickable.

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