Linux:获取窗口边框高度 [英] Linux : Get window border height

问题描述

我尝试在bash脚本中获取窗口的最大大小(即屏幕的大小减去屏幕边缘的面板的大小).我正在使用Kubuntu，但是如果它可以在任何linux系统上都可以，那就太好了.

I try to get in a bash script the maximal size of a window (i.e. the size of the screen minus the panels on the edges of the screen). I am using Kubuntu but if it could work for any linux system it would be great.

当前，我的解决方案是通过wmctrl最大化活动窗口:

Currently, my solution is to maximize the active window via wmctrl :

wmctrl -r :ACTIVE: -b add,maximized_horz,maximized_vert

然后通过xwininfo获取窗口的大小:

and then get the size of the window thanks to xwininfo :

xwininfo -id $(xdotool getactivewindow)

不幸的是，我没有得到窗口的大小，而是得到窗口的大小及其边界(如果删除边界，则得到期望的值).

Unfortunately, I don't get the size of the window but the size of the window and it's border (if I remove the border, I get the expected value).

所以我的问题是:

1-是否有删除窗口边框的命令? (我只知道手动操作)

1 - Is there a command to remove the border of a window ? (I only know how to do it manually)

2-是否有更好的方法可以做到这一点? (如果可以在不最大化窗口的情况下做到这一点，那就太好了

2 - Is there a better way to do this ? (if it can be done without maximizing a window it could be great)

预先感谢您的帮助

推荐答案

我意识到我所说的 border 实际上是标题栏...如果我使用xwininfo -stats，我确实会边框宽度(在我的情况下为0).标题栏的高度(最大化窗口后)是在字段 Absolute left-left 中获得的.以下是预期的高度:

I realised that what I was calling border was in fact the title bar... If I use xwininfo -stats I indeed get the border width (0 in my case). The title bar height (after maximizing the window) is obtained in the field Absolute upper-left. The following gives me the expected height :

eval $(xwininfo -id $(xdotool getactivewindow) | sed -n -e "s/^  Height: \+\([0-9]\+\).*/Height=\1/p" -e "s/^  Absolute upper-left Y:  \+\([0-9]\+\).*/HeightTitleBar=\1/p")
Height=$(($Height+$HeightTitleBar))

感谢您的帮助！

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