在Ruby中将多个代码块作为参数传递 [英] Passing multiple code blocks as arguments in Ruby

问题描述

我有一个采用代码块的方法.

I have a method which takes a code block.

def opportunity
  @opportunities += 1
  if yield
    @performances +=1
  end
end

我这样称呼它:

opportunity { @some_array.empty? }

但是如何将其传递给一个以上的代码块，以便可以两次使用yield，就像这样:

But how do I pass it more than one code block so that I could use yield twice, something like this:

def opportunity
  if yield_1
    @opportunities += 1
  end
  if yield_2
    @performances +=1
  end
end

和:

opportunity {@some_other_array.empty?} { @some_array.empty? }

我知道这个例子可以在没有屈服的情况下完成，但这只是为了说明.

I am aware that this example could be done without yield, but it's just to illustrate.

推荐答案

您本身不能传递多个块，但可以传递多个proc或lambda:

You can't pass multiple blocks, per se, but you can pass multiple procs or lambdas:

使用1.9语法:

opportunity ->{ @some_array.empty? }, ->{ @some_other_array.empty? }

以及方法本身:

def opportunity(lambda1, lambda2)
  if lambda1.()
    @opportunities += 1
  end
  if lambda2.()
    @performances += 1
  end
end

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