如何在不创建新生成器的情况下使用Python将新输入获取到生成器 [英] How to get new input to generator in Python without create a new generator

问题描述

我尝试编写获取列表并使用yield语句生成所有这些转换的代码.

I try to write code that gets a list and generates all of this transformations by using yield statement.

问题是，当我想使用send函数将新的输入获取到生成器时，我会继续获取旧的输入.

The problem is when I want to get new input to generator by using send function, I continue to get the old input.

def permute(items):
    permutations = [x for x in itertools.permutations(items)]
    permutations.sort()
    for n in permutations:
        yield (n)

g = permute(['b','a','c'])
print(next(g)) #('a', 'b', 'c')
print(next(g)) #('a', 'c', 'b')
g.send(['e','q','c'])
print(next(g)) #('b', 'c', 'a') need to be ('c', 'e', 'q')

如何在不创建新生成器的情况下清空排列列表并重复排列排列列表的步骤?

How can I empty the permutation list and repeat to sorting permutations list step without create a new generator?

推荐答案

为什么不仅仅创建一个permute类型的新对象并使用它

Why not just create a new object of type permute and use it

import itertools
def permute(items):
    permutations = [x for x in itertools.permutations(items)]
    permutations.sort()
    for n in permutations:
        yield (n)

g = permute(['b','a','c'])
print(next(g)) #('a', 'b', 'c')
print(next(g)) #('a', 'c', 'b')

g =  permute(['e','q','c'])
print(next(g)) #('b', 'c', 'a') need to be ('c', 'e', 'q')
#I get ('c', 'e', 'q')

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