红宝石案例陈述与比较 [英] ruby case statement with comparison

问题描述

有没有一种方法可以将case语句与ruby中的整数比较一起使用?我发现了很多比较字符串的示例，但是下面的case示例由于语法错误而失败.

Is there a way to use a case statement with integer comparisons in ruby? I have found lots of examples comparing strings, but my case example below fails with syntax errors.

def get_price_rank(price)
    case price
    when <= 40
        return 'Cheap!'
    when 41..50 
        return 'Sorta cheap'
    when 50..60
        return 'Reasonable'
    when 60..70
        return 'Not cheap'
    when 70..80
        return 'Spendy'
    when 80..90
        return 'Expensive!'
    when >= 90
        return 'Rich!'
    end
end

推荐答案

在case..when块中，除===之外，您无法执行任何比较.因此，我将按照以下方式编写您的代码:

In case..when block you can't perform any comparisons except ===. So I'd write your code as below :

def get_price_rank(price)
    case price
    when 41..50 
        'Sorta cheap'
    when 50..60
        'Reasonable'
    when 60..70
        'Not cheap'
    when 70..80
        'Spendy'
    when 80..90
        'Expensive!'
    else
        if price >= 90
         'Rich!'
        elsif price <= 40
         'Cheap!'
        end
    end
end

return是隐式，因此无需提及.

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