python中的集合不区分大小写 [英] case insensitive for sets in python

问题描述

我有一个由多个列表生成的列表.该组合列表包含最终用户生成的名称.因此，包含相似的名称，但具有不同的大写/小写字符. 我想过滤掉包含相同字符的名称，而只将第一个保留在原始列表中.

I have a list that is generated from multiple lists. This combined list contains names that are generated by end users. Therefore contain similar names, but with different upper/lower case characters. I want to filter out the names that contain same characters and just keep the first found in the original list.

例如，我有以下列表:

L0 = ['A_B Cdef', 'A_B Cdef', 'A_B Cdef', 'A_B CdEF', 'A_B CDEF','a_B CdEF', 'A_b CDEF', 'GG_ooo', 'a1-23456']

如果我跑步:

L1 = list(set(L0))

我得到:

['a1-23456', 'A_B Cdef', 'A_B CdEF', 'A_B CDEF', 'a_B CdEF', 'A_b CDEF', 'GG_ooo']

我只想保留具有相同字符的名字中的第一个.

I would like to keep just the first of the names that have same characters.

所以我的结果是:

['a1-23456', 'A_B Cdef', 'GG_ooo']

如果我使用.lower()，则.upper()会得到列表，但是名称是小写/大写.

If I use .lower(), .upper() I get the list, but the names are lower/upper cased.

我只想消除重复项"，而不考虑区分大小写的方法.

I just want to eliminate "duplicates" without considering case sensitive approach.

非常感谢您的帮助.

谢谢！

推荐答案

请改用散列，我认为您无法轻松地使用集合来完成该操作.

Use hash instead, I don't think you can accomplish that easily with sets.

L0 = {value.lower(): value for value in L0[::-1]}.values()

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