复制JS对象并过滤掉某些属性的最简单方法 [英] Simplest way to copy JS object and filter out certain properties

问题描述

如果我有一个JS对象，并且我想创建一个新对象，该对象将复制所有属性(除了需要过滤掉的属性黑名单)，最简单的方法是什么?

If I have a JS object, and I'd like to create a new object which copies over all properties except for a blacklist of properties that need to be filtered out, what's the simplest way to do it?

所以我会做类似的事情

originalObject.copyAndFilter('a', 'b')

将获取原始对象，将其复制，并确保属性a和b不在新对象中.

Which would take the original object, copy it, and make sure properties a and b aren't in the new object.

我正在通过Babel使用ES2015/2016，因此如果它提供了更简单的方法也可以使用.

I'm using ES2015/2016 through Babel so if it provides an even simpler way that would work too.

推荐答案

您可以使用

You could use Set and delete the unwanted properties.

var object = { a: 1, b: 2, c: 3, d: 4 },
    filteredObject = {},
    p = new Set(Object.keys(object));
    blacklist = ['a', 'b'];

blacklist.forEach(a => p.delete(a));

[...p].forEach(k => filteredObject[k] = object[k]);
console.log(filteredObject);

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