JS:筛选对象数组以进行部分匹配 [英] JS: Filter object array for partial matches

问题描述

是否可以过滤与搜索字符串匹配的那些对象?

Is it possible to filter for those objects, which matches for a search string?

const arr = [
    { title: 'Just an example' },
    { title: 'Another exam'},
    { title: 'Something different'}
]

我尝试过

arr.filter(x => { return x.title === searchStr });

但这将仅过滤完全匹配项，但是我需要找到所有部分匹配项. let searchStr = 'exam'应该给我两个对象(第一个和第二个)，let searchStr = 'examp'应该给我一个对象.

But this will filter only exact matches, but I need to find all partial matches. let searchStr = 'exam' should give me two objects (first and second), let searchStr = 'examp' should give me only one object as the result.

推荐答案

根据您的问题，我假设您还希望同时匹配字符串的大写和小写版本，因此RegExps是正确的(但不是唯一的)选择

From your question I will assume you also want to match both uppercase and lowercase versions of your string, so here RegExps are the right (but not the only) choice.

首先，定义一个不区分大小写的 RegExp i标志 a>，在循环之外(这避免了在每次迭代时重新创建新的RegExp实例):

First, define a case-insensitive RegExp with the i flag, outside of the loop (this avoids re-creating a new RegExp instance on each iteration):

 const regexp = new RegExp(searchStr, 'i');

然后，您可以使用 RegExp过滤列表#test ( String#match 也可以):

Then you can filter the list with RegExp#test (String#match would work too):

arr.filter(x => regexp.test(x.title))

String#includes解决方案:

您还可以使用 .includes 的String方法，将两个字符串都转换为小写，然后再进行比较:

String#includes solution:

You could also use the .includes method of String, converting both strings to lowercase before comparing them:

arr.filter(x => x.title.toLowerCase().includes(searchStr.toLowerCase()))

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