获取在参数中解构的对象 [英] Get object that was destructured in parameter

问题描述

假设我有一个函数，该函数将经过分解的对象作为箭头函数中的参数:

Suppose I have a function that takes a destructured object as a parameter in an arrow function:

const myFunc = ({a, b, c}) => {
};

是否存在某种语法或语法，也可以让我将整个对象作为单个值获得?由于箭头功能未绑定arguments，因此无法使用该功能.

Is there anyway or syntax that would allow me to get that whole object as a single value as well? Since the arrow function doesn't bind arguments, I can't use that.

是否可以命名，类似以下内容:

Is it possible to name it, something along the lines of:

const myFunc = (allArgs: {a, b, c}) => {
    console.log(allArgs);
};
myFunc({a:1, b:2, c:3}); // Output: {a:0, b:1, c: 2}

很显然，这不是一个破坏交易的方法，并且有很多变通办法(要么不使用箭头功能，不分解，或者在需要时重新创建对象)，但我想知道为了方便起见.

Obviously, this isn't a deal breaker and there are plenty of workarounds (either don't use an arrow function, don't destructure, or recreate the object when I need it), but I'd like to know for convenience sake.

推荐答案

您可以很容易地破坏单个参数.您失去了参数中简洁的解构语法的优势，但是它仍然很容易而且仍然很清楚:

You could destructure a single param quite easily. You lose the advantage of the terse destructuring syntax in the arguments, but it's easy and still clear:

const myFunc = (allArgs) => {
    const {a, b, c} = allArgs;
    console.log(allArgs);
};

或者，考虑是否需要箭头功能.如果您不需要访问词法this，也许不错的老式function() {}可以解决问题，并可以访问arguments.

Alternatively, consider whether you need an arrow function. If you don't need access to the lexical this perhaps a good old-fashioned function() {} will do the trick and give you access to arguments.

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