将Sentinel-1 SAR图像的像素位置转换为地理坐标(纬度，经度) [英] Converting pixel position to geographical coordinates (lat, long) for a Sentinel-1 SAR image

问题描述

如何从Sentinel-1合成孔径雷达(SAR)卫星图像的x，y位置获取地理坐标?

How can i get the geographical coordinates from x,y position in a Sentinel-1 Synthetic Aperture Radar (SAR) satellite image?

例如，我可以将下载的图像信息sg设置为

For example, I can access a downloaded image info sg as

from snappy import ProductIO
from snappy import PixelPos 
path='path_name'
product = ProductIO.readProduct(path)
sg = product.getSceneGeoCoding()

但是我怎么能使用sg中获得所需点(x，y)的纬度和经度. com/senbox-org/snap-engine/tree/master/snap-python/src/main/resources"rel =" nofollow noreferrer> ESA在Python中的快照引擎?

But how can I get latitude and longitude for a desired point (x, y) in sg using ESA's snap engine within Python?

推荐答案

使用下面的自定义函数，我们可以轻松地将图像sg中的任何点转换为其坐标(纬度，经度):

Using the custom function below, we can easily convert any point inside our image sg to its coordinates (latitude,longitude):

def LatLon_from_XY(ProductSceneGeoCoding, x, y):
    #From x,y position in satellite image (SAR), get the Latitude and Longitude
    geopos = ProductSceneGeoCoding.getGeoPos(PixelPos(x, y), None)
    latitude = geopos.getLat()
    longitude = geopos.getLon()
    return latitude, longitude

UPD: 由于各种快照版本更新，上述功能可能无法正常工作.以下功能在大多数情况下都可以正常工作.

UPD: Because of various snap version updates, function above may not be working properly. Function below should work most of the times.

def LatLon_from_XY(product, x, y):
    geoPosType = jpy.get_type('org.esa.snap.core.datamodel.GeoPos')
    geocoding = product.getSceneGeoCoding()
    geo_pos = geocoding.getGeoPos(snappy.PixelPos(x, y), geoPosType())
    if str(geo_pos.lat)=='nan':
        raise ValueError('x, y pixel coordinates not in this product')
    else:
        return geo_pos.lat, geo_pos.lon

例如对于给定的sg乘积，我们可以获得像素(x = 12000，y = 2000)的坐标为

E.g. for the given sg product, we can get coordinates of pixel (x=12000, y=2000) as

latitude, longitude = LatLon_from_XY(sg, 12000, 2000)

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