如何制作RealmList< String>可包裹的? [英] How to make RealmList<String> Parcelable?
本文介绍了如何制作RealmList< String>可包裹的?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
@Parcelize open class TestClass(
@SerialName("title")
var title: String,
@SerialName("list")
var list: RealmList<String>
) : RealmObject() { ... }
如何在此实现中打包"list"
变量?
它说,即使我添加@RawValue
,也无法打包这种类型的值.
这里有什么选择?一个带有解释的例子将是完美无缺的.
How can I parcelize "list"
variable in this implementation?
It says, that it's not possible to parcel this type of value even if I add @RawValue
.
What's the alternative here? An example with explanation would be flawless.
推荐答案
类似于此方法,你可以做
fun Parcel.readStringRealmList(): RealmList<String>? = when {
readInt() > 0 -> RealmList<String>().also { list ->
repeat(readInt()) {
list.add(readString())
}
}
else -> null
}
fun Parcel.writeStringRealmList(realmList: RealmList<String>?) {
writeInt(when {
realmList == null -> 0
else -> 1
})
if (realmList != null) {
writeInt(realmList.size)
for (t in realmList) {
writeString(t)
}
}
}
那你就可以做
object StringRealmListParceler: Parceler<RealmList<String>?> {
override fun create(parcel: Parcel): RealmList<String>? = parcel.readStringRealmList()
override fun RealmList<String>?.write(parcel: Parcel, flags: Int) {
parcel.writeStringRealmList(this)
}
}
现在您可以做
@Parcelize
open class TestClass(
@SerialName("title")
var title: String = "",
@SerialName("list")
var list: @WriteWith<StringRealmListParceler> RealmList<String>? = null
) : RealmObject(), Parcelable { ... }
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