如何使用Selenium和Python根据用户输入查找元素? [英] How to find an element with respect to the user input using Selenium and Python?

问题描述

以下是HTML结构:

<div class='list'>
  <div>
    <p class='code'>12345</p>
    <p class='name'>abc</p>
  </div>
  <div>
    <p class='code'>23456</p>
    <p class='name'>bcd</p>
  </div>
</div>

并且有一个config.py供用户输入.如果用户在config.code中输入23456，Selenium python如何选择第二个对象?我正在使用find_by_css_selector()定位并选择对象，但是它只能选择第一个对象，即 Code ='12345'.我尝试使用find_by_link_text()，但这是一个<p>元素，而不是<a>元素.任何人都可以帮助.....

And there is a config.py for user input. If the user input 23456 to config.code, how can the selenium python select the second object? I am using find_by_css_selector() to locate and select the object, but it can only select the first object, which is Code='12345'. I tried to use find_by_link_text(), but it is a <p> element not <a> element. Anyone can help.....

推荐答案

使用 WebDriverWait 用于visibility_of_element_located()，则可以使用以下任一定位器策略:

To locate the element with respect to the input by the user using Selenium and python you need to to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

• 在XPATH中使用变量:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='" +user_input+ "']")))

在XPATH中使用%s:

Using %s in XPATH:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='%s']"% str(user_input))))

在XPATH中使用format():

Using format() in XPATH:

user_input = '23456'
element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='list']//div/p[@class='code' and text()='{}']".format(str(user_input)))))

注意:您必须添加以下导入:

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

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