Yii2:基于相关表中的另一个字段自动填充字段 [英] Yii2: auto fill fields based on another field from related table
问题描述
我有一个MySQL表和模型patient_entry，其中包含字段patient_name，city和state.我还有另一个表/模型health_card，其中也包含patient_name，city和state.
I have a MySQL table and model patient_entry which contains fields patient_name, city and state. I also have another table/model health_card which also contains patient_name, city and state.
假设patient_entry表已经用patient_name，city和state填充.
Suppose the patient_entry table is already filled with patient_name, city and state.
当我以health_card形式输入数据时，当我通过与patient_entry表相关的下拉字段选择patient_name时，我希望自动填充相关的city和state字段
When I am entering data in health_card form, when I select the patient_name via drop-down field related to patient_entry table, I want the related city and state fields to be auto-filled.
我的health_card的_form.php看起来像这样:
<head>
<script>
$this->registerJs("$('#healthcard-patient_name').on('change',function(){
$.ajax({
url: '".yii\helpers\Url::toRoute("HealthCard/patient")."',
dataType: 'json',
method: 'GET',
data: {id: $(this).val()},
success: function (data, textStatus, jqXHR) {
$('#healthcard-city').val(data.city);
$('#healthcard-pincode').val(data.pin);
},
beforeSend: function (xhr) {
alert('loading!');
},
error: function (jqXHR, textStatus, errorThrown) {
console.log('An error occured!');
alert('Error in ajax request');
}
});
});");
</script>
</head>
根据建议，我在控制器中添加了以下内容:
And in the controller I have added, as per the suggestion, this:
public function actionPatient($id){
// you may need to check whether the entered ID is valid or not
$model= \app\models\PatientEntry::findOne(['id'=>$id]);
return \yii\helpers\Json::encode([
'city'=>$model->disrict_city,
'pin'=>$model->pin_code
]);
}
推荐答案
您所需要的只是调用AJAX请求以获取所需的字段.就像下面这样:
All you need is calling an AJAX request to get needed fields. Just act like below:
-
(我不知道您的型号名称)来查看您的表格，并查看您的
patient_name字段的id是什么.通常是modelname-fieldname.我假设您的型号名称为Patient.因此，patient_name的ID为patient-patient_name.
(I do not know your model name)take a look at your form and see what is the
idof yourpatient_namefield. It is usuallymodelname-fieldname. I assume that your model name isPatient. So, the id ofpatient_namewould bepatient-patient_name.
添加ajax请求(在您的视图中).
Add an ajax request (in your view).
调用AJAX的代码如下所示:
The code for calling AJAX could look just like below:
$this->registerJs("$('#patient-patient_name').on('change',function(){
$.ajax({
url: '".yii\helpers\Url::toRoute("controllerName/patient")."',
dataType: 'json',
method: 'GET',
data: {id: $(this).val()},
success: function (data, textStatus, jqXHR) {
$('#patient-city').val(data.city);
$('#patient-state').val(data.state);
},
beforeSend: function (xhr) {
alert('loading!');
},
error: function (jqXHR, textStatus, errorThrown) {
console.log('An error occured!');
alert('Error in ajax request');
}
});
});");
注意:
- 使用您自己的代码更改上述代码中的 ControllerName .
- 我假设
city和state字段的ID具有以下ID:相对地patient-city和state-city. - 患者是您控制者中的一项操作
- 您可能需要删除警报|日志并对上面的代码进行一些自定义
-
我没有考虑任何清理代码的条件.请确保用户数据正确.
- Change the ControllerName in above code with your own.
- I assumed that the id of
cityandstatefields has the following id(s):patient-cityandstate-cityrelatively. - patient is an action in your controller
- You may need to remove alerts|logs and do some customization on above code
I didn't consider any conditions for code cleaning. Please make sure that user data is correct.
- 最后，将动作代码添加到您的控制器中.
操作代码:
public function actionPatient($id){
// you may need to check whether the entered ID is valid or not
$model= \app\models\Patient::findOne(['id'=>$id]);
return \yii\helpers\Json::encode([
'city'=>$model->city,
'state'=>$model->state
]);
}
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