从变量打印mysql查询结果 [英] Printing result of mysql query from variable

问题描述

所以我早些时候用php写了这个，但是每次我尝试echo $ test时，我都只获得资源ID5.有人知道如何从变量中实际打印出mysql查询吗?

So I wrote this earlier (in php), but everytime I try echo $test", I just get back resource id 5. Does anyone know how to actually print out the mysql query from the variable?

$dave= mysql_query("SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)") or die(mysql_error());
print $dave;

推荐答案

这将打印出查询:

$query = "SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)";

$dave= mysql_query($query) or die(mysql_error());
print $query;

这将打印出结果:

$query = "SELECT order_date, no_of_items, shipping_charge, SUM(total_order_amount) as test FROM `orders` WHERE DATE(`order_date`) = DATE(NOW()) GROUP BY DATE(`order_date`)";

$dave= mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_assoc($dave)){
    foreach($row as $cname => $cvalue){
        print "$cname: $cvalue\t";
    }
    print "\r\n";
}

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