如何在PHP中分页Mysql表 [英] How to paginate a table of Mysql in PHP
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问题描述
我在mysql中有一张表. 因为它有很多行，所以我想将每10行放在一个页面中，然后通过单击链接向我显示下10行. 有什么解决办法吗?
I have a table in mysql. Because it has many rows I want to put each 10 rows in a page and by clicking a link show me next 10 rows. Is there any solution?
推荐答案
这真的非常棒它是如此简单！无需上大量课！我很高兴:D
it is so simple! no need to work with huge classes! I'm Happy:D
<!DOCTYPE html>
<html lang="en">
<head>
<title>Paginate</title>
</head>
<body>
<form method='get'>
<?php
$connection = Mysql_connect( 'server', 'user', 'pass' );
if ( ! $connection ) {
echo 'connection is invalid';
} else {
Mysql_select_db( 'DB', $connection );
}
//Check if the starting row variable was passed in the URL or not
if ( ! isset( $_GET['startrow'] ) or ! is_numeric( $_GET['startrow'] ) ) {
//We give the value of the starting row to 0 because nothing was found in URL
$startrow = 0;
//Otherwise we take the value from the URL
} else {
$startrow = (int) $_GET['startrow'];
}
//This part goes after the checking of the $_GET var
$fetch = mysql_query( "SELECT * FROM sample LIMIT $startrow, 10" ) or
die( mysql_error() );
$num = Mysql_num_rows( $fetch );
if ( $num > 0 ) {
echo '
<table border=2>';
echo '
<tr>
<td>ID</td>
<td>Drug</td>
<td>quantity</td>
</tr>
';
for ( $i = 0; $i < $num; $i ++ ) {
$row = mysql_fetch_row( $fetch );
echo '
<tr>';
echo "
<td>$row[0]</td>
";
echo "
<td>$row[1]</td>
";
echo "
<td>$row[2]</td>
";
echo '
</tr>
';
}//for
echo '
</table>
';
}
//Now this is the link..
echo '<a href="' . $_SERVER['PHP_SELF'] . '?startrow=' . ( $startrow + 10 ) . '">Next</a>';
$prev = $startrow - 10;
//only print a "Previous" link if a "Next" was clicked
if ( $prev >= 0 ) {
echo '<a href="' . $_SERVER['PHP_SELF'] . '?startrow=' . $prev . '">Previous</a>';
}
?>
</form>
</body>
</html>
通过rickyduck的方式链接也很好
By the way link of rickyduck was good too
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