MySQL:使用介于中间条件中的日期作为结果 [英] MySQL: Using the dates in a between condition for the results
问题描述
我有一条执行此操作的SQL语句
I have a SQL statement in which I do this
... group by date having date between '2010-07-01' and '2010-07-10';
结果如下:
sum(test) day
--------------------
20 2010-07-03
120 2010-07-07
33 2010-07-09
42 2010-07-10
所以我有这些结果,但是有可能我可以写一条语句,在这种情况下,每天在介于"条件下返回这样的结果行:
So I have these results, but is it possible, that I can write a statement that returns me for every day in the "between" condition a result row in this kind:
sum(test) day
--------------------
0 2010-07-01
0 2010-07-02
20 2010-07-03
0 2010-07-04
0 2010-07-05
0 2010-07-06
120 2010-07-07
... ...
42 2010-07-10
否则,如果这不可能,则必须在程序逻辑中进行.
Otherwise, if this is not possible, I have to do it in my program logic.
非常感谢&最好的问候.
Thanks a lot in advance & Best Regards.
更新:如果我向您展示完整的SQL语句,也许会更好:
Update: Perhaps it will be better if I will show you the full SQL statement:
select COALESCE(sum(DUR), 0) AS "r", 0 AS "opt", DATE_FORMAT(date, '%d.%m.%Y') AS "day" from (
select a.id as ID, a.dur as DUR, DATE(FROM_UNIXTIME(REVTSTMP / 1000)) as date,
a_au.re as RE, a_au.stat as STAT from b_c
join c on b_c.c_id = c.id
join a on c.id = a.c_id
join a_au on a.id = a_au.id
join revi on a_au.re = revi.re
join (
select a.id as ID, DATE(FROM_UNIXTIME(REVTSTMP / 1000)) as date,
max(a_au.re) as MAX_RE from b_c
join c on b_c.c_id = c.id
join a on c.id = a.c_id
join a_au on a.id = a_au.id
join revi on a_au.re = revi.re
where b_c.b_id = 30 group by ID, date) x on
x.id = a.id and x.date = date and x.MAX_RE = a_au.rev
where a_au.stat != 7
group by ID, x.date)
AS SubSelTable where date between '2010-07-01' and '2010-07-15' group by date;
更新: 我的新SQL语句(-> Dave Rix):
Update: My new SQL statement (-> Dave Rix):
select coalesce(`theData`.`real`, 0) as 'real', 0 as 'opt', DATE_FORMAT(`DT`.`ddDate`, '%d.%m.%Y') as 'date'
from `dimdates` as DT
left join (
select coalesce(sum(DUR), 0) AS 'real', 0 AS 'opt', date
from (
select a.id as ID, a.dur as DUR, DATE(FROM_UNIXTIME(REVTSTMP / 1000)) as date, a_au.RE as RE, a_au.stat as STAT
from b_c
join c on b_c.c_id = c.id
join a on c.id = a.c_id
join a_au on a.id = a_au.id
join revi on a_au.RE = revi.RE
join (
select a.id as ID, DATE(FROM_UNIXTIME(REVTSTMP / 1000)) as date, max(a_au.RE) as MAX_RE
from b_c
join c on b_c.c_id = c.id
join a on c.id = a.c_id
join a_au on a.id = a_au.id
join revi on a_au.RE = revi.RE
where b_c.b_id = 30 GROUP BY ID, date
) x
on x.id = a.id and x.date = date and x.MAX_RE = a_au.RE
where a_au.stat != 20
group by ID, x.date
) AS SubTable
where date between '2010-07-01' and '2010-07-10' group by date) AS theData
ON `DT`.`ddDate` = `theData`.`date` where `DT`.`ddDate` between '2010-07-01' and '2010-07-15';
推荐答案
查看我对以下问题的回答;
Check out my answer to the following question;
这可能就是您要寻找的:)
This may be just what you are looking for :)
您可以按如下方式修改您的查询(您可以对此进行整合,但是这种方式更简单!)
You can modify your query above as follows (you could integrate this, but this way is simpler!);
SELECT COALESCE(`theData`.`opt`, 0), `DT`.`myDate`
FROM `dateTable` AS DT
LEFT JOIN (
... INSERT YOUR QUERY HERE ...
) AS theData
ON `DT`.`myDate` = `theData`.`date`
,您还需要将查询中的DATE_FORMAT(date, '%d.%m.%Y') AS "day"
更改为date
例如
and you will also need to change the DATE_FORMAT(date, '%d.%m.%Y') AS "day"
in your query to just date
E.g.
select COALESCE(sum(DUR), 0) AS "r", 0 AS "opt", `date` from
对于@OMG Ponies答案,您将需要用大量的数据行预先填充dateTable
!
As for @OMG Ponies answer, you will need to pre-populate the dateTable
with plenty of rows of data!
有人知道我如何将该表的SQL转储发布为可以附加的文件吗?它很大,但是很有用...
Does anyone know how I can post my SQL dump of this table as a file which can be attached? It's quite big, but can be useful...
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