基于多个复选框运行查询 [英] Run a query based on multiple checkboxes

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本文介绍了基于多个复选框运行查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试基于多个复选框运行查询.这是表单上的复选框的一部分.

I am trying to run a query based on multiple checkboxes. This is a snippet of the checkboxes on the form.

<td><strong>
        <input name="criteria[Buffet]" type="checkbox" id="Buffet" value="1"/>
        <label for="Buffet">Buffet</label>
        </strong></td>
      <td><strong>
        <input name="criteria[Breakfast]" type="checkbox" id="Breakfast" value="1"/>
        <label for="Breakfast">Breakfast</label>
        </strong></td>
      <td><strong>
        <input name="criteria[BYOB]" type="checkbox" id="BYOB" value="1" />
        <label for="BYOB">BYOB</label>
        </strong></td>

这是结果页面上的php脚本....

This is the php script on the result page....

<?php
require "congig.php";
if(isset($_POST['criteria']) && !empty($_POST['criteria'])){ 
    foreach($_POST['criteria'] as $key=>$value){ 
        if($value==1) $criteria[] = "'DetailName'='".mysql_escape_string($key)."'";
        } 
        $criteria = implode(' OR ', $criteria); 
        } 
        if(!$rs=mysql_query("SELECT tblLocations.CityID, tblRestaurants.RestName, tblLocations.Street,          
        tblLocations.Phone, tblLocations.Price, tblLocations.Rating, tblDetails.DetailName
        FROM (tblRestaurants INNER JOIN tblLocations ON tblRestaurants.RestID = tblLocations.RestID)            
        INNER JOIN (tblLocDet INNER JOIN tblDetails ON tblLocDet.DetailID = tblDetails.DetailID)
        ON tblLocations.LocationID = tblLocDet.LocID
        WHERE tblLocations.CityID='16'
        AND $criteria
        ORDER BY tblRestaurants.RestName ASC"))
        {
echo "Cannot parse query";
}
elseif(mysql_num_rows($rs) == 0) {
echo "No records found";
}
else {
echo "<table id=\"myTable\" table width=\"710\" class=\"beautifuldata\" align=\"Left\" cellspacing=\"0\">\n";
echo "<thead>\n<tr>";
echo "<th>PLACE</th>";
echo "<th>ADDRESS</th>";
echo "<th>PHONE</th>";
echo "<th>PRICE</th>";
echo "<th>RATING</th>";
echo "</tr>\n</thead>\n";
while($row = mysql_fetch_array($rs)) {
echo"<tr>
<td><strong><a href='$row[RestPage]'>$row[RestName]</a></strong></td>
<td>$row[Address]</td>
<td>$row[Phone]</td>
<td>$row[Price]</td>
<td>$row[Rating]</td>
</tr>\n";
}
echo "</table><br />\n";
}
?>

关于为什么我没有得到任何结果的任何建议?

Any suggestion on why I am not getting any results?

推荐答案

问题的核心似乎是因为您将列DetailName括在单引号中:"'DetailName'='"当应为"DetailName='"

The core of your problem appears to be the fact you're surrounding the column DetailName in single quotes: "'DetailName'='" when all it should be is "DetailName='"

关于安全性,我想指出,您用来强制输入对MySQL友好的函数mysql_escape_string()年代久远,并且充满安全漏洞.相反,我建议使用更安全的实现:mysql_real_escape_string().下面的代码示例利用了更新,更安全的功能.

On a note of security, I would like to point out that the function mysql_escape_string() you're using to force input to be mysql-friendly is old and riddled with security holes. Instead, I'd recommend using the much safer implementation: mysql_real_escape_string(). The code examples below make use of the newer, safer function.

但是,与这些问题分开,我建议采用稍有不同的方法,从长远来看,该方法更易于阅读和管理.

Separate from those issues however, I'd recommend taking a slightly different approach which will be easier to read and much easier to manage in the long run.

对于初学者,我建议在所有复选框上使用相同的名称,并使用DetailName作为值而不是键:

For starters, I'd recommend using the same name on all checkboxes, and using the DetailName as the value rather than as the key:

<td>
    <input name="criteria[]" type="checkbox" id="Buffet" value="Buffet" />
    <strong><label for="Buffet">Buffet</label></strong>
</td>
<td>
    <input name="criteria[]" type="checkbox" id="Breakfast" value="Breakfast" />
    <strong><label for="Breakfast">Breakfast</label></strong>
</td>
<td>
    <input name="criteria[]" type="checkbox" id="BYOB" value="BYOB" />
    <strong><label for="BYOB">BYOB</label></strong>
</td>

接下来,使用输入的值而不是键,我们现在可以生成我们的子句.非常有效:

Next, using the values of your inputs rather than the keys, we can now generate our clause. Very efficiently:

// Runs mysql_real_escape_string() on every value encountered.
$clean_criteria = array_map('mysql_real_escape_string', $_REQUEST['criteria']);
// Convert the array into a string.
$criteria = implode("','", $clean_criteria);

最后,在您的查询中,为提高效率和可读性,建议使用IN运算符而不是OR运算符:

Finally, in your query, I'd recommend using the IN operator rather than the OR operator for efficiency and readability:

SELECT
    tblLocations.CityID, tblRestaurants.RestName, tblLocations.Street, tblLocations.Phone, tblLocations.Price, tblLocations.Rating, tblDetails.DetailName
FROM
    (
        tblRestaurants
    INNER JOIN
        tblLocations ON tblRestaurants.RestID = tblLocations.RestID
    )            
INNER JOIN
    (
        tblLocDet
    INNER JOIN
        tblDetails ON tblLocDet.DetailID = tblDetails.DetailID
    ) ON tblLocations.LocationID = tblLocDet.LocID
WHERE tblLocations.CityID='16' AND tblDetails.DetailName IN ($criteria)
ORDER BY tblRestaurants.RestName ASC

这是将我建议的修改与您的逻辑结合在一起的整个PHP方面:

Here is the whole PHP side of things combining the modifications I suggest with your logic:

<?php
require "congig.php";
if(!empty($_POST['criteria'])) { // empty() checks if the value is set before checking if it's empty.
    foreach($_POST['criteria'] as $key=>$value){ 
        // Runs mysql_real_escape_string() on every value encountered.
        $clean_criteria = array_map('mysql_real_escape_string', $_REQUEST['criteria']);
        // Convert the array into a string.
        $criteria = implode("','", $clean_criteria);
    }

    $rs = mysql_query("
        SELECT
            tblLocations.CityID, tblRestaurants.RestName, tblLocations.Street, tblLocations.Phone, tblLocations.Price, tblLocations.Rating, tblDetails.DetailName
        FROM
            (
                tblRestaurants
            INNER JOIN
                tblLocations ON tblRestaurants.RestID = tblLocations.RestID
            )            
        INNER JOIN
            (
                tblLocDet
            INNER JOIN
                tblDetails ON tblLocDet.DetailID = tblDetails.DetailID
            ) ON tblLocations.LocationID = tblLocDet.LocID
        WHERE tblLocations.CityID='16' AND tblDetails.DetailName IN ($criteria)
        ORDER BY tblRestaurants.RestName ASC
    ");
    if(!$rs) {
        echo "Cannot parse query";
    } else if(mysql_num_rows($rs) == 0) {
        echo "No records found";
    } else {
        echo "<table id=\"myTable\" table width=\"710\" class=\"beautifuldata\" align=\"Left\" cellspacing=\"0\">\n";
        echo "<thead>\n<tr>";
        echo "<th>PLACE</th>";
        echo "<th>ADDRESS</th>";
        echo "<th>PHONE</th>";
        echo "<th>PRICE</th>";
        echo "<th>RATING</th>";
        echo "</tr>\n</thead>\n";
        while($row = mysql_fetch_array($rs)) {
            echo"<tr>
            <td><strong><a href='$row[RestPage]'>$row[RestName]</a></strong></td>
            <td>$row[Address]</td>
            <td>$row[Phone]</td>
            <td>$row[Price]</td>
            <td>$row[Rating]</td>
            </tr>\n";
        }
        echo "</table><br />\n";
    }
}

这篇关于基于多个复选框运行查询的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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