routerLink绝对网址 [英] routerLink absolute url
问题描述
来自角度文档:
router link指令始终将提供的输入视为增量 到当前网址.
The router link directive always treats the provided input as a delta to the current url.
例如，如果当前URL是/user/(box//aux:team).然后
以下链接<a [routerLink]="['/user/jim']">Jim</a>将生成
链接/user/(jim//aux:team).
For instance, if the current url is /user/(box//aux:team). Then the
following link <a [routerLink]="['/user/jim']">Jim</a> will generate
the link /user/(jim//aux:team).
那么您如何创建指向/user/jim的链接?
So how do you create a link to /user/jim ?
我尝试了['/user/jim', { outlets: { aux: null }}]，但是这不起作用.
即使有效，它也不是最佳解决方案.我宁愿寻找一种导航到绝对URL的方法，而不是取消可能渠道.
I tried ['/user/jim', { outlets: { aux: null }}] but this isn't working.
Even if it worked it wouldn't have been a optimal solution. I'm rather looking for a way to navigate to an absolute url than cancelling possibles outlets.
在同一主题上，我有一个指向根目录的链接:routerLink="/"就是这样做的，它重定向到我的应用程序的根目录，而没有像绝对链接这样的出口.有趣的是，我不是特别希望特定链接具有该行为，因此保持所有出口路线都很好...
On the same subject I have a link to the root : routerLink="/" that does just that, it redirect to the root of my application without any outlets like an absolute link. What's funny here is I don't specially want that behavior for that particular link, keeping any outlets routes was fine...
推荐答案
截至2018年8月，角度文档说:
As of August, 2018, Angular docs say:
- 如果第一段以/开头，则路由器将从应用程序的根目录查找路由.
- 如果第一段以./开头，或不以斜杠开头，则路由器将查找当前段的子段 激活的路线.
- 如果第一段以../开头，则路由器将上升一个级别.
- If the first segment begins with /, the router will look up the route from the root of the app.
- If the first segment begins with ./, or doesn't begin with a slash, the router will instead look in the children of the current activated route.
- And if the first segment begins with ../, the router will go up one level.
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