使用SQLAlchemy的多个联接 [英] Multiple joins with SQLAlchemy
本文介绍了使用SQLAlchemy的多个联接的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个数据库模型...
I have this database model...
class Distributor(Base):
__tablename__ = 'distributor'
id = Column(Integer, primary_key=True)
commercial_address_id = Column(Integer, ForeignKey('addresses.id'), nullable=False, unique=True)
invoice_address_id = Column(Integer, ForeignKey('addresses.id'), nullable=False, unique=True)
commercial_address = relationship(Address, lazy="noload", foreign_keys=[commercial_address_id])
invoice_address = relationship(Address, lazy="noload", foreign_keys=[invoice_address_id])
class Address(Base):
__tablename__ = 'address'
id = Column(Integer, primary_key=True)
address_name = Column(String(64))
country_id = Column(Integer, ForeignKey('countries.id'), nullable=False)
country = relationship(Country, lazy="noload")
class Country(Base):
__tablename__ = 'country'
id = Column(Integer, primary_key=True)
code = Column(Integer)
...然后我对数据库进行查询...
...then I do the query to the database...
alias_commercial_address = aliased(Distributor.invoice_address)
alias_commercial_address_country = aliased(Address.country)
alias_invoice_address = aliased(Distributor.commercial_address)
alias_invoice_address_country = aliased(Address.country)
return Distributor.query\
.outerjoin(alias_commercial_address, Distributor.commercial_address)\
.outerjoin(alias_commercial_address_country, Address.country)\
.outerjoin(alias_invoice_address, Distributor.invoice_address)\
.outerjoin(alias_invoice_address_country, Address.country)\
.options(contains_eager(Distributor.commercial_address, alias=alias_commercial_address)
.contains_eager(Address.country, alias=alias_commercial_address_country),
contains_eager(Distributor.invoice_address, alias=alias_invoice_address)
.contains_eager(Address.country, alias=alias_invoice_address_country))\
.all()
...但是框架错误地生成了查询...
...but the framework generates the query incorrectly...
SELECT ... FROM distributors
LEFT OUTER JOIN addresses AS addresses_1 ON addresses_1.id = distributors.commercial_address_id
LEFT OUTER JOIN countries AS countries_1 ON countries_1.id = addresses_1.country_id
LEFT OUTER JOIN addresses AS addresses_2 ON addresses_2.id = distributors.invoice_address_id
LEFT OUTER JOIN countries AS countries_2 ON countries_2.id = addresses_1.country_id
...最后一个JOIN应该是...
...the last JOIN should be...
向左加入其他国家/地区,作为国家_2到国家_2.id =地址_2.country_id
我尝试了不同的方法来创建SQL查询,但是我无法正确生成查询.知道我的错误在哪里吗?
I have tried different ways to create the SQL query, but I can not get to generate the query correctly. Any idea where is my error?
谢谢!
推荐答案
进一步的联接基于您创建的别名:
Base your further joins on the aliases you've created:
Distributor.query\
.outerjoin(alias_commercial_address, Distributor.commercial_address)\
.outerjoin(alias_commercial_address_country, alias_commercial_address.country)\
.outerjoin(alias_invoice_address, Distributor.invoice_address)\
.outerjoin(alias_invoice_address_country, alias_invoice_address.country)\
.options(contains_eager(Distributor.commercial_address, alias=alias_commercial_address)
.contains_eager(alias_commercial_address.country, alias=alias_commercial_address_country),
contains_eager(Distributor.invoice_address, alias=alias_invoice_address)
.contains_eager(alias_invoice_address.country, alias=alias_invoice_address_country))\
.all()
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