如何将GRANT与变量一起使用? [英] How to use GRANT with variables?

问题描述

我在MySql中同时使用GRANT和变量遇到一些麻烦.

I have some troubles with GRANT and variables together in MySql.

SET @username := 'user123', @pass := 'pass123';

GRANT USAGE ON *.* TO @username@'%' IDENTIFIED BY @pass;
GRANT INSERT (header1, header2, headern) ON `data` TO @username@'%';
GRANT SELECT (header1, header2) ON `data2` TO @username@'%';

我想在脚本开始时将用户名和密码放入变量中，然后在GRANT中使用它们

I'd like to put username and password into variables at the begining of the script and then later use them in GRANT

所以代替这个:

GRANT USAGE ON *.* TO 'user123'@'%' IDENTIFIED BY 'pass123';

我想使用这样的东西:

GRANT USAGE ON *.* TO @username@'%' IDENTIFIED BY pass;

如果有人可以向我展示正确的陈述，我将不胜感激. 谢谢你！

I'd really appreciate, if someone could show me the proper statements. Thank you in advence!

推荐答案

SET @object = '*.*';
SET @user = '''user1''@''localhost''';

SET @query = CONCAT('GRANT UPDATE ON ', @object, ' TO ', @user);
PREPARE stmt FROM @query;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

---

DROP PROCEDURE IF EXISTS `test`.`spTest`$$

CREATE DEFINER=`root`@`localhost` PROCEDURE `spTest`( varLogin char(16), varPassword char(64) )
BEGIN
    DECLARE varPasswordHashed CHAR(41);
    SELECT PASSWORD(varPassword) INTO varPasswordHashed;

    # Any of the following 3 lines will cause the creation to fail
    CREATE USER varLogin@'localhost' IDENTIFIED BY varPassword;
    GRANT USAGE ON test.* TO varLogin@'localhost' IDENTIFIED BY varPassword;
    GRANT USAGE ON test.* TO varLogin@'localhost' IDENTIFIED BY PASSWORD varPasswordHashed;

    ## The following 3 lines won't cause any problem at create time
    CREATE USER varLogin@'localhost' IDENTIFIED BY 'AnyPassordString';
    GRANT USAGE ON test.* TO varLogin@'localhost' IDENTIFIED BY 'AnyPassordString';
    GRANT USAGE ON test.* TO varLogin@'localhost' IDENTIFIED BY PASSWORD  'AnyPassordString';  
END$$

DELIMITER;

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